SQL刪除重複記錄的N種方法

查詢及刪除重複記錄的SQL語句
查詢及刪除重複記錄的SQL語句
1、查找表中多餘的重複記錄,重複記錄是根據單個字段(peopleId)來判斷
select * from people
where peopleId in (select   peopleId from   people group by   peopleId having count(peopleId) > 1)
2、刪除表中多餘的重複記錄,重複記錄是根據單個字段(peopleId)來判斷,只留有rowid最小的記錄
delete from people
where peopleId in (select   peopleId from people group by   peopleId   having count(peopleId) > 1)
and rowid not in (select min(rowid) from   people group by peopleId having count(peopleId )>1)
3、查找表中多餘的重複記錄(多個字段)
select * from vitae a
where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
4、刪除表中多餘的重複記錄(多個字段),只留有rowid最小的記錄
delete from vitae a
where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

5、查找表中多餘的重複記錄(多個字段),不包含rowid最小的記錄
select * from vitae a
where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
(二)
比方說
在A表中存在一個字段“name”,
而且不同記錄之間的“name”值有可能會相同,
現在就是需要查詢出在該表中的各記錄之間,“name”值存在重複的項;
Select Name,Count(*) From A Group By Name Having Count(*) > 1
如果還查性別也相同大則如下:
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

 


(1)通過建立臨時表來實現

 

SQL>create table temp_emp as (select distinct * from employee)

SQL> truncate table employee; (清空employee表的數據)

 

SQL> insert into employee select * from temp_emp; (再將臨時表裏的內容插回來)

 


( 2)通過唯一rowid實現刪除重複記錄.在Oracle中,每一條記錄都有一個rowid,rowid在整個數據庫中是唯一的,rowid確定了每條記錄是在Oracle中的哪一個數據文件、塊、行上。在重複的記錄中,可能所有列的內容都相同,但rowid不會相同,所以只要確定出重複記錄中那些具有最大或最小rowid的就可以了,其餘全部刪除。

 

SQL>delete from employee e2 where rowid not in (
        select max(e1.rowid) from employee e1 where

        e1.emp_id=e2.emp_id and e1.emp_name=e2.emp_name and e1.salary=e2.salary);--這裏用min(rowid)也可以。

 


SQL>delete from employee e2 where rowid <(
        select max(e1.rowid) from employee e1 where
        e1.emp_id=e2.emp_id and e1.emp_name=e2.emp_name and

                  e1.salary=e2.salary);


(3)也是通過rowid,但效率更高。

 

SQL>delete from employee where rowid not in (
        select max(t1.rowid) from employee t1 group by

         t1.emp_id,t1.emp_name,t1.salary);--這裏用min(rowid)也可以。

 http://hi.baidu.com/zhaochenbo/blog/item/690dd12a436da439d52af159.html

發表評論
所有評論
還沒有人評論,想成為第一個評論的人麼? 請在上方評論欄輸入並且點擊發布.
相關文章