http://blog.csdn.net/huangxy10/article/details/8193953 在這裏發現了總結的很有用的根據自己需要的時間查詢數據
但是它那個查昨天的那個有問題，我給改了，其它有問題再說
今天
select * from 表名 where to_days(時間字段名) = to_days(now());
昨天
SELECT * from t_se_score_generate where TO_DAYS(now())-TO_DAYS(createtime)<=1 AND TO_DAYS(now())-TO_DAYS(createtime)> 0 ORDER BY createtime DESC;
7天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(時間字段名)
近30天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(時間字段名)
本月
SELECT * FROM 表名 WHERE DATE_FORMAT( 時間字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )
上一月
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 時間字段名, '%Y%m' ) ) =1
#查詢本季度數據
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查詢上季度數據
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查詢本年數據
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查詢上年數據
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
查詢當前這周的數據
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
查詢上週的數據
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
查詢當前月份的數據
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
查詢距離當前現在6個月的數據
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查詢上個月的數據
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')
select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())
select *
from user
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
select *
from [ user ]
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
select *
from [ user ]
where pudate between 上月最後一天
and 下月第一天
where date(regdate) = curdate();
select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30