實現對16位數的反轉（倒序變換

一個算法
unsigned short SwapBit16(unsigned short Data)
{
	int i;
	unsigned short  Dest;

	Dest = 0;
	for(i=0;i<8;i++)
		Dest |= ((((Data&(1<<i))?1:0)<<(15-i)) + (((Data&(1<<(15-i)))?1:0)<<i));

	return Dest;

}

上面這個函數實現對16位數的反轉（倒序變換）。
實現的思路，可以使用如下方法來測試一下。

這個是一個測試函數
#include <stdio.h>
int main(void )
{
	int i;
	unsigned short  Data=45918;

	int Dest = 0;
	for(i=0;i<8;i++){
		 printf("Date1 is 0x%x \n",(((Data&(1<<i))?1:0)<<(15-i)));
		 printf("Date2 is 0x%x \n",(((Data&(1<<(15-i)))?1:0)<<i));
		 printf("Date2 and Date1 is 0x%x \n",((((Data&(1<<i))?1:0)<<(15-i)))+(((Data&(1<<(15-i)))?1:0)<<i));
		Dest |= ((((Data&(1<<i))?1:0)<<(15-i)) + (((Data&(1<<(15-i)))?1:0)<<i));
	}
      	printf("the 0b1011001101011110 end the Date is 0x%x\n",Dest);
	return Dest;

}
下面是測試信息結果：
Date1 is 0x0 
Date2 is 0x1 
Date2 and Date1 is 0x1 
Date1 is 0x4000 
Date2 is 0x0 
Date2 and Date1 is 0x4000 
Date1 is 0x2000 
Date2 is 0x4 
Date2 and Date1 is 0x2004 
Date1 is 0x1000 
Date2 is 0x8 
Date2 and Date1 is 0x1008 
Date1 is 0x800 
Date2 is 0x0 
Date2 and Date1 is 0x800 
Date1 is 0x0 
Date2 is 0x0 
Date2 and Date1 is 0x0 
Date1 is 0x200 
Date2 is 0x40 
Date2 and Date1 is 0x240 
Date1 is 0x0 
Date2 is 0x80 
Date2 and Date1 is 0x80 
the 0b1011001101011110 end the Date is 0x7acd

從結果可看出，實現思想是15<-->0,14<-->1,13<-->2,......8<-->7相交換，具體怎麼實現的，你自己可以深入分析一下。。