LeetCode 243 shortest word distance -python(easy)-lock

題目來源：

Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list.
For example,
Assume that words = ["practice", "makes", "perfect", "coding", "makes"].
Given word1 = “coding”, word2 = “practice”, return 3.
Given word1 = "makes", word2 = "coding", return 1.
Note:

You may assume that word1 does not equal to word2, and word1 and word2 are both in the list.

題意：給定一個數組和兩個單詞word1,word2,返回兩者最近的距離word1不等於word2,但是兩者可能在數組中出現多次

題目分析：

  本題可以考慮在遍歷數組的時候記錄word1，word2的位置，並且每次都計算最新的最小值。

由於本題需要解鎖才能提交，這樣這裏我直接拷貝別人的java代碼：

public class Solution {  
    public int shortestDistance(String[] words, String word1, String word2) {  
        if (words == null) return -1;  
        int idx1 = -1, idx2 = -1;  
        int diff = words.length;  
        for (int i = 0; i < words.length; i++) {  
            if (words[i].equals(word1)) {  
                idx1 = i;                  
            } else if (words[i].equals(word2)) {  
                idx2 = i;                  
            }  
            if(idx1!=-1&&idx2!=-1){  
                diff = Math.min(diff,Math.abs(idx1-idx2));  
            }  
        }  
        return diff;  
    }  
}