【Java語言學習】之遞歸、非遞歸前序、中序、後續遍歷二叉樹

轉載:http://blog.csdn.net/haijiaoxiaowu/article/details/4851059

文章非常不錯,幫了大忙,講解很詳細

package com.nowcoder.校招真題2016;

import java.util.Stack;  
import java.util.HashMap;  
  
public class BinTree {  
    private char date;  
    private BinTree lchild;  
    private BinTree rchild;  
  
    public BinTree(char c) {  
        date = c;  
    }  
  
    // 先序遍歷遞歸   
    public static void preOrder(BinTree t) {  
        if (t == null) {  
            return;  
        }  
        System.out.print(t.date);  
        preOrder(t.lchild);  
        preOrder(t.rchild);  
    }  
  
    // 中序遍歷遞歸   
    public static void InOrder(BinTree t) {  
        if (t == null) {  
            return;  
        }  
        InOrder(t.lchild);  
        System.out.print(t.date);  
        InOrder(t.rchild);  
    }  
  
    // 後序遍歷遞歸   
    public static void PostOrder(BinTree t) {  
        if (t == null) {  
            return;  
        }  
        PostOrder(t.lchild);  
        PostOrder(t.rchild);  
        System.out.print(t.date);  
    }  
  
    // 先序遍歷非遞歸   
    public static void preOrder2(BinTree t) {  
    	Stack<BinTree> s = new Stack<BinTree>();  
        while (t != null || !s.empty()) {  
            while (t != null) {  
                System.out.print(t.date);  
                s.push(t);  
                t = t.lchild;  
            }  
            if (!s.empty()) {  
                t = s.pop();  
                t = t.rchild;  
            }  
        }  
    }  
  
    // 中序遍歷非遞歸   
    public static void InOrder2(BinTree t) {  
    	 Stack<BinTree> s = new Stack<BinTree>(); 
        while (t != null || !s.empty()) {  
            while (t != null) {  
                s.push(t);  
                t = t.lchild;  
            }  
            if (!s.empty()) {  
                t = s.pop();  
                System.out.print(t.date);  
                t = t.rchild;  
            }  
        }  
    }  
  
    // 後序遍歷非遞歸   
    public static void PostOrder2(BinTree t) {  
    	Stack<BinTree> s = new Stack<BinTree>(); 
    	Stack<Integer> s2 = new Stack<Integer>();  
        Integer i = new Integer(1);  
        while (t != null || !s.empty()) {  
            while (t != null) {  
                s.push(t);  
                s2.push(new Integer(0));  
                t = t.lchild;  
            }  
            while (!s.empty() && s2.peek().equals(i)) {  
                s2.pop();  
                System.out.print(s.pop().date);  
            }  
  
            if (!s.empty()) {  
                s2.pop();  
                s2.push(new Integer(1));  
                t = s.peek();  
                t = t.rchild;  
            }  
        }  
    }  
  
    public static void main(String[] args) {  
        BinTree b1 = new BinTree('a');  
        BinTree b2 = new BinTree('b');  
        BinTree b3 = new BinTree('c');  
        BinTree b4 = new BinTree('d');  
        BinTree b5 = new BinTree('e');  
  
        /** 
         *      a  
         *     / / 
         *    b   c 
         *   / / 
         *  d   e 
         */  
        b1.lchild = b2;  
        b1.rchild = b3;  
        b2.lchild = b4;  
        b2.rchild = b5;  
  
        BinTree.preOrder(b1);  
        System.out.println();  
        BinTree.preOrder2(b1);  
        System.out.println();  
        BinTree.InOrder(b1);  
        System.out.println();  
        BinTree.InOrder2(b1);  
        System.out.println();  
        BinTree.PostOrder(b1);  
        System.out.println();  
        BinTree.PostOrder2(b1);  
    }  
}  



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