using System;
namespace Pattern
{
/// <summary>
/// Summary description for Class1.
/// </summary>
/*
假設你有三個播音設備.分別使CD 磁帶機,Mp3 它們分別有自己獨立的操作放案.這讓你很頭痛
因爲你必須掌握三套類似卻有相對獨立的方案.那麼我們考慮如何解決*/
public class CDPlay
{
private string SongName;
public CDPlay(string sn)
{
SongName=sn;
}
public void PlayCd()
{
Console.WriteLine("Play Cd" + SongName);
}
public void StopCd()
{
Console.WriteLine("Stop Cd");
}
}
public class RecordPlay
{
private string SongName;
public RecordPlay(string sn)
{
SongName=sn;
}
public void PlayRecord()
{
Console.WriteLine("Play Record" + SongName);
}
public void StopRecord()
{
Console.WriteLine("Stop Record");
}
}
public class Mp3Play
{
private string SongName;
public Mp3Play(string sn)
{
SongName=sn;
}
public void PlayMp3()
{
Console.WriteLine("Play Mp3" + SongName);
}
public void StopMp3()
{
Console.WriteLine("Stop Mp3");
}
}
//下面我們建立統一的界面
public class Facade
{
private Mp3Play mp3;
private RecordPlay rd;
private CDPlay cd;
private string playName;
private string songName;
public string PlayName
{
get{return playName;}
set{playName=value;}
}
public string SongName
{
get{return SongName;}
set{SongName=value;}
}
public Facade(string pn,string sn)
{
playName=pn;
songName=sn;
}
public void play()
{
switch(playName)
{
case "CD":
cd=new CDPlay(songName);
cd.PlayCd();
break;
case "mp3":
mp3=new Mp3Play(songName);
mp3.PlayMp3();
break;
case "Record":
rd=new RecordPlay(songName);
rd.PlayRecord();
break;
}
}
public void stop()
{
switch(playName)
{
case "CD":
cd=new CDPlay(songName);
cd.StopCd();
break;
case "mp3":
mp3=new Mp3Play(songName);
mp3.StopMp3();
break;
case "Record":
rd=new RecordPlay(songName);
rd.StopRecord();
break;
}
}
}
}
//門面模式
Facade facade = new Facade("CD","aaaa");
facade.play();
facade.stop ();
facade.PlayName="mp3";
facade.play();
facade.stop();
facade.PlayName="Record";
facade.play();
facade.stop();