引用、指針的指針、指針的引用

代碼不具備可用性，只是用來測試

#include <iostream>
using namespace std;

class myclass{
public:
	myclass(){};
	~myclass(){};
};

void fun1(myclass* ptr){
	cout<<"調用fun1"<<endl;
	cout<<(myclass*)ptr<<endl;
	ptr = (myclass*)malloc(sizeof myclass);
	cout<<(myclass*)ptr<<endl;
}

void fun2(myclass** ptr){
	cout<<"調用fun2"<<endl;
	cout<<(myclass*)*ptr<<endl;
	*ptr = (myclass*)malloc(sizeof myclass);
	cout<<(myclass*)*ptr<<endl;
}

void fun3(myclass*& ptr){
	cout<<"調用fun3"<<endl;
	cout<<(myclass*)ptr<<endl;
	ptr = (myclass*)malloc(sizeof myclass);
	cout<<(myclass*)ptr<<endl;
}


void main(){
	myclass* p1 = new myclass;
	myclass* p2 = new myclass();//這兩個什麼區別我就不知道了
	fun1(p1);
	cout<<(myclass*)p1<<endl;//p1值沒變
	fun1(p2);
	cout<<(myclass*)p2<<endl;//p2值也沒變
	fun2(&p1);
	cout<<(myclass*)p1<<endl;
	fun2(&p2);
	cout<<(myclass*)p2<<endl;
	fun3(p1);
	cout<<(myclass*)p1<<endl;
	fun3(p2);
	cout<<(myclass*)p2<<endl;
	system("pause");
}