看下面兩句話:
$path_parts = pathinfo($filename);
$title = $path_parts['filename'];
在如果文件名是GBK、GB2312等非UTF-8或ASCI字符集編碼時,獲取的filename屬性是錯誤的。
因此,如果要獲取爭取的屬性,應當先對字符集進行編碼。
$filename = transToUTF8($filename);
$path_parts = pathinfo($filename);
$title = $path_parts['filename'];