使用hibernate時,發現一個錯誤:
at java.lang.Thread.run(Thread.java:748)
Caused by: java.sql.SQLException: Subquery returns more than 1 row
at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:54
SQL:
select
inspection0_.houseInfo_id as col_0_0_,
inspection0_.id as col_1_0_,
inspection0_.agent_id as col_2_0_,
(select
distinct cooperatio2_.id
from
t_cooperationOrder cooperatio2_
where
cooperatio2_.primaryAgent_id=113
and cooperatio2_.status>1
and cooperatio2_.inspectionOrder_id=inspection0_.id ) as col_3_0_,
houseinfo1_.id as id1_35_0_,
inspection0_.id as id1_40_1_,
houseinfo1_.address as address2_35_0_,
houseinfo1_.agreeTotalPrice as agreeTot3_35_0_
from
t_inspectionOrder inspection0_
inner join
t_houseInfo houseinfo1_
on inspection0_.houseInfo_id=houseinfo1_.id
where
(
inspection0_.agent_id=113
or 113 in (
select
cooperatio3_.secondaryAgent_id
from
t_cooperationOrder cooperatio3_
where
cooperatio3_.inspectionOrder_id=inspection0_.id
and cooperatio3_.status>1
)
)
and houseinfo1_.houseStatus=8
and (
inspection0_.status in (
7 , 8
)
)
order by
inspection0_.updateTime desc
解決方法:
以select * from table1 where table1.colums=(select columns from table2);這個sql語句爲例。
1)如果是寫入重複,去掉重複數據。然後寫入的時候,可以加邏輯判斷(php)或者外鍵(mysql),防止數據重複寫入。
(我實際開發中遇到的就是數據重複寫入的情況,在數據庫查到有相同的數據兩條,這不符原本的原本的業務需求)
2)在子查詢條件語句加limit 1,找到一個符合條件的就可以了
select * from table1 where table1.colums=(select columns from table2 limit 1);
3)在子查詢前加any關鍵字
select * from table1 where table1.colums=any(select columns from table2);
(4)select * from table1 where table1.colums=any(select max(columns) from table2);
參考:
https://hedleyproctor.com/2014/08/hibernate-query-limitations-and-correlated-sub-queries/
https://blog.csdn.net/LY_Dengle/article/details/78028166