python 的 zipfile 提供了非常便捷的方法來壓縮和解壓 zip 文件。
例如,在py腳本所在目錄中,有如下文件:
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readability/readability.js readability/readability.txt readability/readability-print.css readability/sprite-readability.png readability/readability.css |
將 readability 目錄中的文件壓縮到腳本所在目錄的 readability.zip 文件中,保持相同的文件結構,然後打印出生成的壓縮包 的文件列表,再用兩種方式分別解壓文件到腳本所在目錄的 output 目錄和 output/bak 目錄中。
腳本如下:
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#!/usr/vin/env
python #
coding: utf-8 """ 壓縮和解壓zip文件 """ import os import zipfile def compress(zip_file,
input_dir): f_zip = zipfile.ZipFile(zip_file, 'w' ) for root,
dirs, files in os.walk(input_dir): for f in files: #
獲取文件相對路徑,在壓縮包內建立相同的目錄結構 abs_path = os.path.join(os.path.join(root,
f)) rel_path = os.path.relpath(abs_path,
os.path.dirname(input_dir)) f_zip.write(abs_path,
rel_path, zipfile.ZIP_STORED) def extract(zip_file,
output_dir): f_zip = zipfile.ZipFile(zip_file, 'r' ) #
解壓所有文件到指定目錄 f_zip.extractall(output_dir) #
逐個解壓文件到指定目錄 for f in f_zip.namelist(): f_zip.extract(f,
os.path.join(output_dir, 'bak' )) def printdir(zip_file): f_zip = zipfile.ZipFile(zip_file, 'r' ) print '==
printdir() ============================' f_zip.printdir() print print '==
namelist() ============================' for f in f_zip.namelist(): print f if __name__ = = '__main__' : zip_file = 'readability.zip' compress(zip_file,
os.path.join(os.getcwd(), 'readability' )) printdirzip_file) extract(zip_file, 'output' )< / pre> |
python暴力破解含密碼的zip壓縮文件
思路:
1.先自己生成一份txt的密碼字典
2.然後讀取出來,一個個的嘗試,當密碼錯誤是,程序會報錯中斷,所以密碼錯誤,要使用pass
3.當解壓縮成功後,中斷程序,輸出正確密碼
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import zipfile import os from threading import Thread import time #壓縮文件的路徑 path = r 'C:\Users\Administrator\Desktop\moeMaid-master.zip' #password='1234' def pojie_zip(path,password): if path[ - 4 :] = = '.zip' : #path
= dir+ '\\' +file #print
path zip = zipfile.ZipFile(path,
"r" ,zipfile.zlib.DEFLATED) #print
zip.namelist() try : #若解壓成功,則返回True,和密碼 zip .extractall(path = 'C:\\Users\\Administrator\\Desktop\\' ,members = zip .namelist()
, pwd = password) print '
----success!,The password is %s'
%
password zip .close() return True except : pass #如果發生異常,不報錯 print 'error' def get_pass(): #密碼字典的路徑 passPath = 'C:\\Users\\Administrator\\Desktop\\zip.txt' passFile = open (passPath, 'r' ) for line in passFile.readlines(): password = line.strip( '\n' ) print 'Try
the password %s'
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password if pojie_zip(path,password): break passFile.close() if __name__ = = '__main__' : start = time.clock() get_pass() print "done
(%.2f seconds)"
%
(time.clock() - start) |
這是我解壓縮一個5.4M文件的速度,其實時間都花在瞭解壓縮上了