想了想,沒啥說的,代碼不算難,涉及到的知識點本文都有說明:
#八皇后問題
board=[
[0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0],
[0,0,0,0,0,0,0,0]
]
total=0;
def can_play(x,y):
#判斷(x,y)座標能否放皇后
#1.判斷x行是否有皇后
for i in range(0,y):
if board[x][i]==1:
return False
#2.判斷y列是否有皇后
for i in range(0,x):
if board[i][y]==1:
return False
#3.判斷左斜是否有皇后
for i in range(0,x):
if x+y-i <= 7 and board[i][x+y-i]==1:
return False
#4.判斷右斜是否有皇后
for index,i in enumerate(range(x-1,-1,-1)):
s_y=y-(index+1)
if s_y >= 0:
if board[i][s_y]==1:
return False
return True
def print_board():
for i in range(8):
for j in range(8):
if board[i][j]==0:
function(){ //技術指標 http://www.fx61.com/faq/muniu/437.html
print("□",end=" ") #print()函數中加一個“空格(end=" ")”,表示不換行
else:
print("■",end=" ")
print()
def put_queen(step):
if step==8:
print_board()
global total
total += 1
print("------------------------")
else:
for i in range(8):
#判斷該位置是否能放當前皇后
if can_play(step,i):
#1.設置現場
board[step][i]=1
#2.開始遞歸
put_queen(step+1)
#3.恢復現場 (非常重要!前面的走,後面的要恢復)
board[step][i]=0
if __name__ == "__main__":
print_board(0) #從第0步開始走
print("總共有{}種方法".format(total)) #Python的變量輸出格式:{} + format()
range是Python的一個內置函數,其作用是“遍歷其中區間中的所有值”,遵循“左閉右開”原則