剪刀石頭布

10:石頭剪刀布

石頭剪刀布是常見的猜拳遊戲。石頭勝剪刀，剪刀

#include <iostream>
using namespace std;
int a[105];
int b[105];
int main(){
int n, x, y;
cin >> n >> x >> y;
int a_win = 0, b_win = 0;
        for (int i = 1; i <= x; i++)
        cin >> a[i];
         for (int i = 1; i <= y; i++)
            cin >> b[i];
     for (int i = 1; i <= n; i++)
        {
            a[i] = a[(i-1)%x +1];
              b[i] = b[(i-1)%y+1];
        if (a[i] == 0 && b[i] == 2)  a_win++;
            else if (a[i] == 0 && b[i] == 5)  b_win++;
            else if (a[i] == 2 && b[i] == 0)  b_win++;
              else if (a[i] == 2 && b[i] == 5)  a_win++;
           else if (a[i] == 5 && b[i] == 0)  a_win++;
            else if (a[i] == 5 && b[i] == 2)  b_win++;
        }
        if (a_win > b_win)  cout << "A" << endl;
         else if (a_win < b_win)  cout << "B" << endl;
        else cout << "draw" << endl;}

              

看似很簡單巧妙支持在；

 a[i] = a[(i-1)%x +1];
  b[i] = b[(i-1)%y+1];

通過+1放在最後保證餘數不可能爲0