var b = new Date();
var c = new Date(b.getFullYear(),b.getMonth(),b.getDate()+30); alert(c.getFullYear()+"-"+(c.getMonth()+1)+"-"+c.getDate())
new Date();時可以傳入參數,就是把字符串轉爲日期。
下面寫下對一個給定的日期增加一個天數之後的日期進行顯示
//給定一個yyyy-mm-dd的日期字符串,然後給定一個天數agreeDays
function test(DateOne,agreeDays){
var ADDTIME=agreeDays;
var OneMonth = DateOne.substring(5,DateOne.lastIndexOf ('-'));
var OneDay = DateOne.substring(DateOne.length,DateOne.lastIndexOf ('-')+1);
var OneYear = DateOne.substring(0,DateOne.indexOf ('-'));
var dt=new Date(OneYear,OneMonth,OneDay);
var dtnow = new Date(dt.getTime()+ADDTIME*24*3600*1000);
//alert(dt30.toLocaleDateString().replace('年','-').replace('月','-').replace('日',''))
var nowYear = dtnow.getFullYear();
var nowMonth = dtnow.getMonth();
var nowDay = dtnow.getDate();
if(parseInt(nowMonth) < 10){
nowMonth = '0'+nowMonth;
}
if(parseInt(nowDay) < 10){
nowDay = '0'+nowDay;
}
alert(nowYear+"-"+nowMonth+"-"+nowDay);
}
返回給定日期agreeDays天后的日期
肯定不是最好的方法。。
讀者如果有,請留言告訴我啊~哈哈~