Stack 簡介
Stack 是一種後進先出的數據結構實現,也就是LIFO(last in first out). 舉個例子吧,大學食堂的大媽會攤煎餅。攤好了就放到桌子上,後面攤好的會疊加到之前一個上。如果有個人來買,大媽通常會把最上面的煎餅給到到你。當然,一般情況她不會從最底下抽一個出來給你。那樣容易把餅子扯爛了,而且從底下拿餅子,就是大媽在演示FIFO(first in firt out)啦。開個玩笑,一般是大家在旁邊等着大媽攤餅子。煎餅果子切克鬧,有錢沒錢來一套。走起。
Stack class
Stack 很單純,只有一個父類 Vector,它通過五個操作擴展了Vector類,這些操作允許將 Vector 視爲 Stack。提供了通常的 推入 push() 和 彈出 pop() 操作,以及一種 查看堆棧頂部項目的方法peek()
public class Stack<E> extends Vector<E> {}
當stack倍創建後,他是不包含任何對象的。Deque接口及其實現提供了一組更完整和一致的LIFO堆棧操作,應優先於此類使用。
Deque stack = new ArrayDeque();
代碼不多,就全部貼上來:
public
class Stack<E> extends Vector<E> {
/**
* Creates an empty Stack.
*/
public Stack() {
}
/**
* Pushes an item onto the top of this stack. This has exactly
* the same effect as:
* <blockquote><pre>
* addElement(item)</pre></blockquote>
*
* @param item the item to be pushed onto this stack.
* @return the <code>item</code> argument.
* @see java.util.Vector#addElement
*/
public E push(E item) {
addElement(item);
return item;
}
/**
* Removes the object at the top of this stack and returns that
* object as the value of this function.
*
* @return The object at the top of this stack (the last item
* of the <tt>Vector</tt> object).
* @throws EmptyStackException if this stack is empty.
*/
public synchronized E pop() {
E obj;
int len = size();
obj = peek();
removeElementAt(len - 1);
return obj;
}
/**
* Looks at the object at the top of this stack without removing it
* from the stack.
*
* @return the object at the top of this stack (the last item
* of the <tt>Vector</tt> object).
* @throws EmptyStackException if this stack is empty.
*/
public synchronized E peek() {
int len = size();
if (len == 0)
throw new EmptyStackException();
return elementAt(len - 1);
}
/**
* Tests if this stack is empty.
*
* @return <code>true</code> if and only if this stack contains
* no items; <code>false</code> otherwise.
*/
public boolean empty() {
return size() == 0;
}
/**
* Returns the 1-based position where an object is on this stack.
* If the object <tt>o</tt> occurs as an item in this stack, this
* method returns the distance from the top of the stack of the
* occurrence nearest the top of the stack; the topmost item on the
* stack is considered to be at distance <tt>1</tt>. The <tt>equals</tt>
* method is used to compare <tt>o</tt> to the
* items in this stack.
*
* @param o the desired object.
* @return the 1-based position from the top of the stack where
* the object is located; the return value <code>-1</code>
* indicates that the object is not on the stack.
*/
public synchronized int search(Object o) {
int i = lastIndexOf(o);
if (i >= 0) {
return size() - i;
}
return -1;
}
/** use serialVersionUID from JDK 1.0.2 for interoperability */
private static final long serialVersionUID = 1224463164541339165L;
}
可以看到,Stack 也是做了同步操作的。