HDU-2055( An easy problem )

原創

2020-02-22 02:00

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

Output

for each case, you should the result of y+f(x) on a line.

Sample Input

6
R 1
P 2
G 3
r 1
p 2
g 3

Sample Output

這道題做了兩次，第一次是在剛學Java沒多久，第二次是現在寫的，從其中也是能感受到一點進步吧。

第一版本：

import java.util.Scanner;

public class Main {

    
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        sc.nextLine();
        int[] aa=new int[52];
        char[] ch=new char[52];
        int A=1;
        int a=-1;
        for(int i=0;i<aa.length;i=i+2){ //用來存字母對應的數字
            aa[i]=A++;
            aa[i+1]=a--;
        }
        int xx=0;
        for(int i=0;i<ch.length;i=i+2){
            //用來存字符
            ch[i]=(char)('A'+xx);
            ch[i+1]=(char)('a'+xx);
            xx++;
        }
        while(n-->0){
            String str=sc.next();
            int y=sc.nextInt();
            int j=0;
            for(;j<aa.length;j++){
                if(str.equals(""+ch[j])){
                    break;
                }
            }
            System.out.println(aa[j]+y);
        }

    }

}

第二版本：

import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Main{
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        Map<String,Object> num=new HashMap<String,Object>();
        for(int i=0;i<26;i++){
            num.put(((char)('a'+i))+"", -(i)-1);
            num.put(((char)('A'+i))+"", i+1);
        }
        while(sc.hasNext()){
            int t=sc.nextInt();
            sc.nextLine();
            while(t-->0){
                String str=sc.nextLine();
                String[] str2=str.split(" +");
                int a1=(int) num.get(str2[0]);
                int a2=Integer.valueOf(str2[1]);
                System.out.println(a1+a2);
            }
        }
    }
}