Given a binary array, find the maximum number of consecutive 1s in this array.
Example 1:
Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
The maximum number of consecutive 1s is 3.
Note:
The input array will only contain 0 and 1.
The length of input array is a positive integer and will not exceed 10,000
class Solution(object):
def findMaxConsecutiveOnes(self, nums):
"""
:type nums: list[int]
:rtype: int
"""
mmax = 0
count = 0
for i in nums:
if i == 1:
count += 1
else:
if count > mmax:
mmax = count
count = 0
if count>mmax:
mmax=count
return mmax
class Solution2(object):
def findMaxConsecutiveOnes(self, nums):
return max(map(len, ''.join(map(str, nums)).split('0'))) #效率低一點,但是比較另類
if __name__ == '__main__':
print Solution().findMaxConsecutiveOnes([1, 1, 0, 1, 1, 1])