spring 框架@Transactional 不回滾 解決辦法

參照路徑

http://stackoverflow.com/questions/17224887/java-spring-transactional-method-not-rolling-back-as-expected

簡單說明一下：

public class Service {
    MyDAO dao;

    public void insertCollection(RecordCollection collection){
        while (collection.size() > 1){
            Record1 record1 = collection.removeFirst();
            Record2 record2 = collection.removeFirst();
            doBoth(record1, record2);
        }
    }

    @Transactional (rollbackFor = Exception.class, propagation = Propagation.REQUIRES_NEW)
    public void doBoth(Record1 record1, Record2 record2){
        method1(record1);
        method2(record2);
    }

    @Transactional(propagation = Propagation.REQUIRED)
    public void method1(Record1 record){
        dao.insertIntoA(record);
    }

    @Transactional(propagation = Propagation.REQUIRED)
    public void method2(Record2 record){
        dao.insertIntoB(record);
    }

    public void setMyDAO(final MyDAO dao) {
        this.dao = dao;
    }
}

就是，如果 @Transactional 在一個類裏面，是不好用的。也就是同一個類裏面，沒有@Transactional的方法調用有@Transactional的方法，不會實現事務功能。

要改成如下（兩個類分開寫）。

public class Foo {
    public void insertCollection(RecordCollection collection){
        Service myService = new Service();
        while (collection.size() > 1){
            Record1 record1 = collection.removeFirst();
            Record2 record2 = collection.removeSecond();
            myService.doBoth(record1, record2);
        }
    }
}

public class Service {
    MyDAO dao;

    @Transactional (rollbackFor = Exception.class, propagation = Propagation.REQUIRES_NEW)
    public void doBoth(Record1 record1, Record2 record2){
        method1(record1);
        method2(record2);
    }

    @Transactional(propagation = Propagation.REQUIRED)
    public void method1(Record1 record){
        dao.insertIntoA(record);
    }

    @Transactional(propagation = Propagation.REQUIRED)
    public void method2(Record2 record){
        dao.insertIntoB(record);
    }

    public void setMyDAO(final MyDAO dao) {
        this.dao = dao;
    }
}

也就是要另外寫一個類，調用含有@Transactional的方法。這樣就好用了。