將一列字符串顯示爲轉換爲多行顯示

將一列字符串顯示爲轉換爲多行顯示？
現在有一個字符串
/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ
參賽過一條sql語句顯示爲
ABC
AA
AD
ABD
JI
CC
ALSKD
ALDKDJ
8行數據。請問各位有辦法實現嗎？謝謝了。

方法一：支持oracle9以上

SELECT rn,
       '/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ/' str,
       SUBSTR('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ/',
              LAG(INSTR('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ/', '/', 1, rn),
                  1,
                  0) OVER(ORDER BY rn) + 1,
              INSTR('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ/', '/', 1, rn) -
              LAG(INSTR('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ/', '/', 1, rn),
                  1,
                  0) OVER(ORDER BY rn) - 1)
  FROM (SELECT LEVEL rn
          FROM DUAL
        CONNECT BY 1 = 1
               AND LEVEL <=
                   LENGTH('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ/') -
                   LENGTH(REPLACE('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ/', '/')));

方法二：支持oracle9以上

select substr('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ', sp, ep - sp) str
  from (select instr('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ', '/', 1, rownum) + 1 sp,
               instr('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ', '/', 1, rownum + 1) ep
          from dual
        connect by rownum <
                   LENGTH('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ/') -
                   LENGTH(REPLACE('/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ/', '/')))
 where ep > 0;
方法三：支持oracle10以上

with a as (select '/ABC/AA/AD/ABD/JI/CC/ALSKD/ALDKDJ' id from dual)
    select regexp_substr(id,'[^/]+',1,rownum) id from a
    connect by  rownum<=length(regexp_replace(id,'[^/]+'))