Android通過PopupMenu定義彈出菜單的位置

效果如圖:



具體實現代碼如下:

package com.example.mytest;

import android.app.Activity;
import android.os.Bundle;
import android.support.v4.app.FragmentActivity;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.PopupMenu;
import android.widget.Toast;

public class MainActivity extends Activity {

	@Override
	protected void onCreate(Bundle savedInstanceState) {
		super.onCreate(savedInstanceState);
		setContentView(R.layout.activity_main);

		Button btn = (Button) findViewById(R.id.btn);

		btn.setOnClickListener(new OnClickListener() {

			@Override
			public void onClick(View v) {
				
				showPopupMenu(v);
			}
		});
	}

	private void showPopupMenu(View view) {
		// View當前PopupMenu顯示的相對View的位置
		PopupMenu popupMenu = new PopupMenu(this, view);

		// menu佈局
		popupMenu.getMenuInflater().inflate(R.menu.main, popupMenu.getMenu());

		// menu的item點擊事件
		popupMenu.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() {
			@Override
			public boolean onMenuItemClick(MenuItem item) {
				Toast.makeText(getApplicationContext(), item.getTitle(), Toast.LENGTH_SHORT).show();
				return false;
			}
		});

		// PopupMenu關閉事件
		popupMenu.setOnDismissListener(new PopupMenu.OnDismissListener() {
			@Override
			public void onDismiss(PopupMenu menu) {
				Toast.makeText(getApplicationContext(), "關閉PopupMenu", Toast.LENGTH_SHORT).show();
			}
		});

		popupMenu.show();
	}

}


發表評論
所有評論
還沒有人評論,想成為第一個評論的人麼? 請在上方評論欄輸入並且點擊發布.
相關文章