Given a 2D integer matrix M representing the gray scale of an image, you need to design a smoother to make the gray scale of each cell becomes the average gray scale (rounding down) of all the 8 surrounding cells and itself. If a cell has less than 8 surrounding cells, then use as many as you can.
Example 1:
Input: [[1,1,1], [1,0,1], [1,1,1]] Output: [[0, 0, 0], [0, 0, 0], [0, 0, 0]] Explanation: For the point (0,0), (0,2), (2,0), (2,2): floor(3/4) = floor(0.75) = 0 For the point (0,1), (1,0), (1,2), (2,1): floor(5/6) = floor(0.83333333) = 0 For the point (1,1): floor(8/9) = floor(0.88888889) = 0
Note:
- The value in the given matrix is in the range of [0, 255].
- The length and width of the given matrix are in the range of [1, 150].
class Solution {
public int[][] imageSmoother(int[][] M) {
int[][] ave = new int[M.length][M[0].length];
for (int i = 0; i < M.length; i++) {
for (int j = 0; j < M[i].length; j++) {
int count =0;
if(j>0){
ave[i][j]+=M[i][j-1];
count++;
}
if(j<M[i].length-1){
ave[i][j]+=M[i][j+1];
count++;
}
if(i>0){
ave[i][j]+=M[i-1][j];
count++;
if(j>0){
ave[i][j]+=M[i-1][j-1];
count++;
}
if(j<M[i].length-1){
ave[i][j]+=M[i-1][j+1];
count++;
}
}
if(i<M.length-1){
ave[i][j]+=M[i+1][j];
count++;
if(j>0){
ave[i][j]+=M[i+1][j-1];
count++;
}
if(j<M[i].length-1){
ave[i][j]+=M[i+1][j+1];
count++;
}
}
ave[i][j]+=M[i][j];
count++;
ave[i][j]/=count;
}
}
return ave;
}
}