使用jQuery獲取到所有複選框的值並用Ajax異步提交數據
<body>
<div>
<input type="checkbox" name="check" value="1"/>複選框1
<input type="checkbox" name="check" value="2"/>複選框2
<input type="checkbox" name="check" value="3"/>複選框3
<br/>
<input type="checkbox" name="check" value="4"/>複選框4
<input type="checkbox" name="check" value="5"/>複選框5
<input type="checkbox" name="check" value="6"/>複選框6
<br/>
<input type="checkbox" name="check" value="7"/>複選框7
<input type="checkbox" name="check" value="8"/>複選框8
<input type="checkbox" name="check" value="9"/>複選框9
<input type="button" id="dosubmit" value="提交">
</div>
</body>
<script>
$('#dosubmit').click(function(){
var checkID = [];
$("input[name='check']:checked").each(function(i){
checkID[i] =$(this).val();
});
$.post('Ajax.php',{checkID:checkID},function(json){
},'json')
})
</script>
