json轉數組出現對象格式解決方法

[{"goods_id":"416","number":"5"},{"goods_id":"162","number":"2"}]  轉化爲

array(2) {
  [0] => array(2) {
    ["goods_id"] => string(3) "268"
    ["number"] => string(1) "3"
  }
  [1] => array(2) {
    ["goods_id"] => string(3) "144"
    ["number"] => string(1) "2"
  }
}

使用：json_decode($goodsStr,true)；  加上true即可解決。