MySQL中, 如何查詢某一天, 某一週，某一月, 某一年的數據.

今天

select * from 表名 where to_days(時間字段名) = to_days(now());
昨天

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 時間字段名) <= 1
近7天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(時間字段名)
近30天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(時間字段名)
本月

SELECT * FROM 表名 WHERE DATE_FORMAT( 時間字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )
上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 時間字段名, '%Y%m' ) ) =1
查詢本季度數據

select * fromht_invoice_informationwhere QUARTER(create_date)=QUARTER(now());
查詢上季度數據

select * fromht_invoice_informationwhere QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
查詢本年數據

select * fromht_invoice_informationwhere YEAR(create_date)=YEAR(NOW());
查詢上年數據

select * fromht_invoice_informationwhere year(create_date)=year(date_sub(now(),interval 1 year));
查詢當前這周的數據

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
查詢上週的數據

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
查詢上個月的數據

select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

select * from user where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ; 

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now()) 

select * from user where MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now()) 

select * from user where YEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = YEAR(now()) and MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now()) 

select * from user where pudate between  上月最後一天  and 下月第一天 

查詢當前月份的數據

select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
查詢距離當前現在6個月的數據

select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

查詢某個月的數據(查詢17年10月份數據)

select * from exam where date_format(starttime,'%Y-%m')='2017-10'

select * from exam where date_format(starttime,'%Y-%m')=date_format('2017-10-05','%Y-%m')