sql模糊查詢帶中括號[ ]字符串及中括號Unclosed character class near index 0 [ ^ 轉義符問題

一、需要模糊查詢帶中括號的字符串，一般寫法失敗：

        SELECT * FROM EvaluationInformation WHERE AnnualNumber LIKE '%[2018]%'；

二、中括號需要通過escape 進行轉義才能查到數據：

       SELECT * FROM EvaluationInformation WHERE AnnualNumber LIKE '%/[2018/]%' escape '/'；

三、中括號需要提前加上‘/’ 進行轉義，用java字符串replace，split轉義失敗：

1、String annualnumber = evaluationInfo.getAnnualnumber();
             if(annualnumber.contains("[")) {
                annualnumber.replaceAll("[","/[");
              }

2、String annualnumber = evaluationInfo.getAnnualnumber();
             if(annualnumber.contains("[")) {
                  annualnumber.replaceAll("\\[","/[");
              }

3、String[] splits = annualnumber.split("[");

四、java  字符串split轉義成功：

String[] splits = annualnumber.split("\\[");
            annualnumber=splits[0];
            for (int i =1; i < splits.length; i++) {
                annualnumber+="/["+splits[i];
            }

     可以使用js轉義：annualnumber.replace("[","/[").replace("]","/]")；，

     如果有多箇中括號，js不能使用replaceAll，放棄使用js轉義；中括號 '[' 或者  ']' 可能放在字符串末尾，使用java後端轉義：

String annualnumber = evaluationInfo.getAnnualnumber();
		if(StringUtils.isNotEmpty(annualnumber)) {
			annualnumber+="1";
			if(annualnumber.contains("[")) {
				String[] splits = annualnumber.split("\\[");
				annualnumber=splits[0];
				for (int i =1; i < splits.length; i++) {
					annualnumber+="/["+splits[i];
				}
			}
			
			if(annualnumber.contains("]")) {
				String[] splits = annualnumber.split("\\]");
				annualnumber=splits[0];
				for (int i =1; i < splits.length; i++) {
					annualnumber+="/]"+splits[i];
				}
			}
			evaluationInfo.setAnnualnumber(annualnumber.substring(0, annualnumber.length()-1));
		}