計算f(n)=1+1/2+1/3+1/4+...+1/n

# include<stdio.h>

int main()
{
   int n;
   scanf("%d",&n);
   int i;
   double sum = 0.0;
   for(i = 1; i<=n; i++){
       
       sum += 1.0/i;
       
   }
   
    printf("f(%d)=%f\n",n,sum);
   
    return 0;
}