Java 解析多層級json 爲map的簡單方法 list-list 無法解析

package com.example.youfang;

import com.alibaba.fastjson.JSONArray;
import com.alibaba.fastjson.JSONObject;
import com.google.gson.*;

import java.util.*;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

/**
 * JSONUtil
 *
 * @author 
 * @date 2018/07/19
 */
public class JSONUtil {
    public static  String abc="{\"header\":{\"version\":\"1.0\",\"transType\":\"W387\",\"submitTime\":\"20180717092002\",\"sessionId\":null,\"clientTraceNo\":\"201807170500001839518200\",\"hostTime\":\"20180717091904\",\"hostTraceNo\":\"8500b868-bbfe-4236-825f-075598aa3f97\",\"returnCode\":\"0000\",\"merchantId\":\"182000899000001\",\"terminalId\":null,\"returnMessage\":\"交易成功\",\"transDirect\":null,\"signMessage\":\"\"},\"body\":{\"hostSettleDate\":\"20180717\",\"voucherType\":\"31\",\"coupons\":[{\"couponsNo\":\"1817503001007701\",\"availTimes\":\"1\",\"activeDate\":\"20180103\",\"expireDate\":\"20190228\",\"password\":\"\",\"voucherType\":\"1\",\"prodID\":\"107511\",\"prodName\":\"胖叔洗車H5支付測試\"},{\"couponsNo\":\"1817503001007701\",\"availTimes\":\"1\",\"activeDate\":\"20180103\",\"expireDate\":\"20190228\",\"password\":\"\",\"voucherType\":\"1\",\"prodID\":\"107511\",\"prodName\":\"胖叔洗車H5支付測試\"}],\"containsSubCoupons\":\"1\"}}\n";

    public static void main(String[] args) {
        System.out.println(abc);
        System.out.println(parseData(abc,"header"));
        System.out.println(parseData(abc,"body"));
        System.out.println(parseData(abc,"body.coupons"));
        System.out.println(parseData(abc,"body.coupons[0].prodName"));
        System.out.println(parseData(abc,"body.coupons[0]"));
    }

    /**
     * @Description: 解析任意結構 json  數據    list-list  無法解析
     * @date  2018/07/19
     * @author zhaolin 趙神
     */
    public static Object parseData(String jsonStr, String key) {
        Map map =(Map)JSONObject.parse(jsonStr);
        String keys[] = key.split("\\.");
        Map temp = map;
        for (int i = 0; i < keys.length; i ++) {
            boolean isEnd = i == keys.length - 1;
            String tempKey = keys[i];
            Matcher m = Pattern.compile("([a-zA-z]+)(\\[)([0-9]*)(\\])").matcher(tempKey);
            if (m.find()) {
                int index = Integer.parseInt(m.group(3));
                List list = (List)temp.get(m.group(1));
                if (isEnd)
                    return list.get(index);
                else
                    temp = (Map)list.get(index);
            } else {
                if (isEnd)
                    return temp.get(keys[keys.length-1]);
                temp = (Map)temp.get(tempKey);
            }
        }
        return null;
    }
}