Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
You are given a target value to search. If found in the array return its index, otherwise return -1.
You may assume no duplicate exists in the array.
分類討論的題目 變形的二分搜索
public class Solution { public int search(int[] A, int target) { if(A==null||A.length==0){ return -1; } int left = 0; int right = A.length-1; int mid = 0; while(left<=right){ mid = left+(right-left)/2; if(A[mid] == target){ return mid; } // it got to be that one of the both side is sorted if(A[mid]<A[right]){ if(target>A[mid] && target<=A[right]){ left = mid+1; }else{ right = mid-1; } }else{ if(target<A[mid] && target>=A[left]){ right = mid-1; }else{ left = mid+1; } } } return -1; } }