之前用二分搜索樹實現了集合
現在使用鏈表實現集合LinkedList
基於二分搜索樹的集合實現
class Node {
E e;
Node left;
Node right;
}
基於LinkedList鏈表的集合實現
class Node {
E e;
Node next;
}
映射
-
存儲(鍵 key,值 value)數據對的數據結構
-
根據鍵(key),尋找值(value)
- 身份證號碼----------------> 人
- 車牌號----------------------> 車
- 數據庫 ID------------------> 信息
- 詞頻統計 單詞------------> 數字
public interface Map<K, V> {
void add(K key, V value);
V remove(K key);
boolean contains(K key);
V get(K key);
void set(K key, V newValue);
int getSize();
boolean isEmpty();
}
LinkedListMap 基於鏈表的映射實現
package map;
public class LinkedListMap<K, V> implements Map<K, V> {
private class Node {
private K key;
private V value;
public Node next;
public Node(K key, V value, Node next) {
key = key;
value = value;
this.next = next;
}
public Node(K key, V value) {
this(key, value, null);
}
public Node() {
this(null, null, null);
}
@Override
public String toString(){
return key.toString() + " : " + value.toString();
}
}
private Node dummyHead;
private int size;
public LinkedListMap(){
dummyHead = new Node();
size = 0;
}
private Node getNode(K key){
Node cur = dummyHead.next;
while(cur != null){
if(cur.key.equals(key))
return cur;
cur = cur.next;
}
return null;
}
@Override
public void add(K key, V value) {
Node node = getNode(key);
if(node == null){
dummyHead.next = new Node(key, value, dummyHead.next);
size ++;
} else {
node.value = value;
}
}
@Override
public V remove(K key) {
Node prev = dummyHead;
while(prev.next != null){
if(prev.next.key.equals(key))
break;
prev = prev.next;
}
if(prev.next != null){
Node delNode = prev.next;
prev.next = delNode.next;
delNode.next = null;
size --;
return delNode.value;
}
return null;
}
@Override
public boolean contains(K key) {
return getNode(key) != null;
}
@Override
public V get(K key) {
Node node = getNode(key);
return node == null ? null : node.value;
}
@Override
public void set(K key, V newValue) {
Node node = getNode(key);
if(node == null)
throw new IllegalArgumentException(key + " doesn't exist!");
node.value = newValue;
}
@Override
public int getSize() {
return size;
}
@Override
public boolean isEmpty() {
return size == 0;
}
}
BSTMap 基於二分搜索是樹的映射實現
public class BSTMap<K extends Comparable<K>, V> implements Map<K, V> {
private class Node{
public K key;
public V value;
public Node left, right;
public Node(K key, V value){
this.key = key;
this.value = value;
left = null;
right = null;
}
}
private Node root;
private int size;
public BSTMap(){
root = null;
size = 0;
}
// 向以node爲根的二分搜索樹中插入元素(key, value),遞歸算法
// 返回插入新節點後二分搜索樹的根
private Node add(Node node, K key, V value){
if(node == null){
size ++;
return new Node(key, value);
}
if(key.compareTo(node.key) < 0)
node.left = add(node.left, key, value);
else if(key.compareTo(node.key) > 0)
node.right = add(node.right, key, value);
else // key.compareTo(node.key) == 0
node.value = value;
return node;
}
// 返回以node爲根節點的二分搜索樹中,key所在的節點
private Node getNode(Node node, K key){
if(node == null)
return null;
if(key.equals(node.key))
return node;
else if(key.compareTo(node.key) < 0)
return getNode(node.left, key);
else // if(key.compareTo(node.key) > 0)
return getNode(node.right, key);
}
@Override
public void add(K key, V value) {
}
@Override
public V remove(K key) {
return null;
}
@Override
public boolean contains(K key) {
return getNode(root, key) != null;
}
@Override
public V get(K key) {
Node node = getNode(root, key);
return node == null ? null : node.value;
}
@Override
public void set(K key, V newValue) {
Node node = getNode(root, key);
if(node == null)
throw new IllegalArgumentException(key + " doesn't exist!");
node.value = newValue;
}
@Override
public int getSize() {
return size;
}
@Override
public boolean isEmpty() {
return size == 0;
}
// 返回以node爲根的二分搜索樹的最小值所在的節點
private Node minimum(Node node){
if(node.left == null)
return node;
return minimum(node.left);
}
// 刪除掉以node爲根的二分搜索樹中的最小節點
// 返回刪除節點後新的二分搜索樹的根
private Node removeMin(Node node){
if(node.left == null){
Node rightNode = node.right;
node.right = null;
size --;
return rightNode;
}
node.left = removeMin(node.left);
return node;
}
// 從二分搜索樹中刪除鍵爲key的節點
@Override
public V remove(K key){
Node node = getNode(root, key);
if(node != null){
root = remove(root, key);
return node.value;
}
return null;
}
private Node remove(Node node, K key){
if( node == null )
return null;
if( key.compareTo(node.key) < 0 ){
node.left = remove(node.left , key);
return node;
} else if (key.compareTo(node.key) > 0 ){
node.right = remove(node.right, key);
return node;
} else { // key.compareTo(node.key) == 0
// 待刪除節點左子樹爲空的情況
if(node.left == null){
Node rightNode = node.right;
node.right = null;
size --;
return rightNode;
}
// 待刪除節點右子樹爲空的情況
if(node.right == null){
Node leftNode = node.left;
node.left = null;
size --;
return leftNode;
}
// 待刪除節點左右子樹均不爲空的情況
// 找到比待刪除節點大的最小節點, 即待刪除節點右子樹的最小節點
// 用這個節點頂替待刪除節點的位置
Node successor = minimum(node.right);
successor.right = removeMin(node.right);
successor.left = node.left;
node.left = node.right = null;
return successor;
}
}
}