DFS，拓撲排序

DFS僞代碼：

DFS(G,s)
    for each vertex v in V(G)
        status[v] = WHITE
        /******其他初始化******/
    for each vertex v in V(G)
        if(status[v]==WHITE)
            DFS-VISIT(v)
 
DFS-VISIT(v)
    status[v] = GRAY
    for each vertex t in Adj(v)
        if status[t] = WHITE
            DFS-VISIT(t)
            /******其他操作******/
    status[v] = BLACK

關於DFS的C語言版和拓撲排序以及是否存在環，引用一位大牛的博客：

http://blog.csdn.net/acceptedxukai/article/details/6959882