D - 匹配
The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.
Input
The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.
Output
For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.
Sample Input
3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN
Sample Output
1
3
0
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <vector>
#include <cstring>
#include <queue>
using namespace std;
const int max1 = 1e6+4, max2 = 1e4+4;
int Next[max2], s[max2], ss[max1];
int m, n;
int getNext(){
Next[0] = Next[1] = 0;
for(int i = 1; i < m - 1; i++){
int j = Next[i];
while(j && s[i] != s[j])
j = Next[j];
if(s[i] == s[j])
Next[i+1] = j + 1;
else
Next[i+1] = 0;
}
}
int Find(){
int j = 0;
for(int i = 0; i < n; i++){
while(j && s[j] != ss[i])
j = Next[j];
if(s[j] == ss[i])
j++;
if(j == m)
return i - m + 1 + 1;
}
return -1;
}
int main(){
#ifdef TEST
freopen("test.txt", "r", stdin);
#endif // TEST
int T;
cin >> T;
while(T--){
memset(Next, 0, sizeof(Next));
cin >> n >> m;
for(int i = 0; i < n; i++)
scanf("%d", &ss[i]);
for(int i = 0; i < m; i++)
scanf("%d", &s[i]);
getNext();
cout << Find() << endl;
}
return 0;
}