Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊
n/2 ⌋
times.
You may assume that the array is non-empty and the majority element always exist in the array.
class Solution {
public:
int majorityElement(vector<int> &num) {
int ans = num[0];
int cnt = 1;
for(int i = 1;i < num.size();i ++){
if(cnt == 0){
ans = num[i];
cnt = 1;
continue;
}
if(num[i] == ans)
cnt ++;
else
cnt --;
}
return ans;
}
};