新生晚會
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 13920 Accepted Submission(s): 4781
每組數據包含兩個整數N(來報名的人數,1<=N<=30),M(節目需要的人數0<=M<=30)
1
#include<stdio.h>
#include<algorithm>
#include<iostream>
using namespace std;
double home(double n,double m)
{
double i,j,a=1.0,b=1.0;
double sum = 1.0;
j = m;
while(j--)
{
a=n;
b=m;
sum=sum*a/b;
n--;
m--;
}
return sum;
}
int main()
{
double n,m,t;
cin >> t;
while(t--)
{
cin >> n >> m;
if(m>n)
{
cout << 0 << endl;
continue;
}
printf("%.0lf\n",home(n,m));
}
return 0;
}