UVA 11462 Age Sort

Age Sort 
Input: Standard Input 
Output: Standard Output 
You are given the ages (in years) of all people of a country with at least 1 year of age. You know that 
no individual in that country lives for 100 or more years. Now, you are given a very simple task of
sorting all the ages in ascending order. 
Input 
There are multiple test cases in the input file. Each case starts with an integer n (0<n<=2000000), the 
total number of people. In the next line, there are n integers indicating the ages. Input is terminated 
with a case where n = 0. This case should not be processed. 
Output  
For each case, print a line with n space separated integers. These integers are the ages of that country
sorted in ascending order. 
Warning: Input Data is pretty big (~  25 MB) so use faster IO. 
Sample Input                             Output for Sample Input 
5 
3 4 2 1 5 
5 
2 3 2 3 1 
0 
1 2 3 4 5 
1 2 2 3 3 
The memory limit for this problem is 2 Megabyte only. 
Problem Setter: Mohammad Mahmudur Rahman 
Special Thanks: Shahriar Manzoor 

內存有限制，計數排序，加上讀入優化更快。

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main()
{
  int n,x,c[101];
  char s[5];
  while(~scanf("%d",&n),n)
  {
    memset(c,0,sizeof(c));
    for(int i=0;i<n;i++)
    {
      x=0;
      scanf("%s",s);
      for(int k=0;s[k];k++)
      {
        x=x*10+s[k]-'0';
      }
      c[x]++;
    }
    for(int i=0;i<=100;i++)
    {
      for(int j=0;j<c[i];j++)
      {
        printf("%d",i);
        n--;
        if(n)printf(" ");
      }
    }
    printf("\n");
  }
}