第九周實驗報告（三）定義分數類中的運算符的重載。

/*

* 程序的版權和版本聲明部分

* Copyright (c) 2011, 煙臺大學計算機學院學生 

* All rights reserved.

* 文件名稱：

定義分數類中的<<、>>運算符的重載，實現輸入輸出，改造源程序中對運算結果的顯示方式，使程序讀起來更自然。

                             

* 作    者：  晁 陽                            

* 完成日期：  2012年 4 月 7 日

* 版 本 號： t.10         

* 對任務及求解方法的描述部分

* 代碼實現

#include<iostream>   
 
using namespace std;
  
int gcd(int m, int n);    
  
class CFraction  
{  
private:  
    int nume;  // 分子  
    int deno;  // 分母  
public:  
    //構造函數及運算符重載的函數聲明  
    CFraction(int nu=0,int de=1);   //構造函數，初始化用    
    void Simplify();                    //化簡（使分子分母沒有公因子）      
    void output();           //輸出：以8/6爲例，style爲0時，輸出8/6；    
    bool operator > (CFraction &t);    
    bool operator < (CFraction &t);    
    bool operator >= (CFraction &t);    
    bool operator <= (CFraction &t);    
    bool operator == (CFraction &t);    
    bool operator != (CFraction &t);    
    CFraction operator+(CFraction &c);     
    CFraction operator-(CFraction &c);  
    CFraction operator*(CFraction &c);    
    CFraction operator/(CFraction &c);  
    CFraction operator-();  
	friend ostream& operator << (ostream&,CFraction &);
	friend istream& operator >> (istream&,CFraction &);
      
};  
istream& operator >> (istream& input,CFraction & c)
{ 
	input>>c.nume>>c.deno;
	return input;
}
ostream& operator << (ostream& output,CFraction & c)
{
	output<<c.nume<<'/'<<c.deno<<endl; 
	return output;
}
CFraction::CFraction(int nu,int de)   //構造函數，初始化用     
{  
       if (de!=0)    
       {    
           nume=nu;    
           deno=de;    
       }    
       else    
       {    
           cerr<<"初始化中發生錯誤，程序退出\n";        
           exit(0);    
       }    
}  
void CFraction::Simplify()                    //化簡（使分子分母沒有公因子）   
{   
    int n;  
    if(nume < 0)    
    {    
        n = gcd(-nume, deno);    
    }    
    else    
    {    
        n = gcd(nume, deno);    
    }    
    
    nume = nume / n;      
    
    deno = deno / n;  
}  
// 求m，n的最大公約數    
int gcd(int m, int n)    
{    
    int r;    
    if (m<n){r=m;m=n;n=r;}    
    while(r=m%n)  // 求m，n的最大公約數    
    {    
        m=n;    
        n=r;    
    }    
    return n;    
}    

bool CFraction::operator > (CFraction &t)  
{  
    CFraction c2,c3;  
    c2.nume =nume*t.deno ;  
    c3.nume =t.nume *deno;  
    if(c2.nume >c3.nume )  
        return true;  
    else  
        return false;  
}  
bool CFraction::operator < (CFraction &t)   
{  
    CFraction c2,c3;  
    c2.nume =nume*t.deno ;  
    c3.nume =t.nume *deno;  
    if(c2.nume <c3.nume )  
        return true;  
    else  
        return false;  
}  
bool CFraction::operator >= (CFraction &t)  
{    
    CFraction c1;    
    c1.nume =nume;  
    c1.deno =deno;  
    if (c1<t)    
        return false;    
    return true;    
}    
  
bool CFraction::operator <= (CFraction &t)  
{    
    CFraction c1;    
    c1.nume =nume;  
    c1.deno =deno;  
    if (c1>t)    
        return false;    
    return true;    
}    
bool CFraction::operator == (CFraction &t)   
{  
    CFraction c1;    
    c1.nume =nume;  
    c1.deno =deno;  
    if (c1<t)    
        return false;    
    if (c1>t)    
        return false;    
    return false;  
}  
  
bool CFraction::operator != (CFraction &t)  
{  
    CFraction c1;    
    c1.nume =nume;  
    c1.deno =deno;  
    if (c1==t)    
        return false;  
    return true;  
}  
CFraction CFraction::operator+(CFraction &c)  
{  
    CFraction c2,c3,c4;  
    c2.nume =nume*c.deno ;  
    c3.nume =c.nume *deno;  
    c2.deno =deno*c.deno ;  
    c3.deno =c.deno *deno;  
    c4.nume=c2.nume +c3.nume ;  
    c4.deno =c2.deno ;  
    c4.Simplify ();  
    return c4;  
}  
CFraction CFraction::operator-(CFraction &c)  
{  
    CFraction c2,c3,c4;  
    c2.nume =nume*c.deno ;  
    c3.nume =c.nume *deno;  
    c2.deno =deno*c.deno ;  
    c3.deno =c.deno *deno;  
    c4.nume=c2.nume -c3.nume ;  
    c4.deno =c2.deno ;  
    c4.Simplify ();  
    return c4;  
}  
CFraction CFraction::operator*(CFraction &c)   
{  
    CFraction c2,c3,c4;  
    c2.nume =nume*c.nume  ;  
    c2.deno =deno*c.deno ;  
    c2.Simplify ();  
    return c2;  
}  
CFraction CFraction::operator/(CFraction &c)  
{  
    CFraction c2,c3;  
    c2.nume =c.deno ;  
    c2.deno =c.nume ;  
    c3.nume =nume*c2.nume ;  
    c3.deno =deno*c2.deno ;  
    c3.Simplify ();  
    return c3;  
}  
CFraction CFraction::operator-()  
{  
    CFraction c2;  
    c2.nume =nume;  
    c2.deno =deno;  
    c2.Simplify ();  
    if(c2.nume<0 || c2.deno<0)  
    {  
        if(c2.nume <0)  
        {  
            c2.nume =-nume;  
        }  
        else  
        {  
            c2.deno =-deno;  
        }  
    }  
    else  
    {  
        c2.nume =-nume;  
        c2.deno =deno;  
    }  
    return c2;  
}  
  
//用於測試的main()函數  
void main()    
{    
    CFraction c1,c2,c;
	cout<<"請您輸入一個分數c1：（以a b的形式輸入）";
	cin>>c1;
	cout<<"請您輸入一個分數c2：（以a b的形式輸入）";
	cin>>c2;
    cout<<"c1爲：";    
    cout<<c1;    
    cout<<"c2爲：";    
    cout<<c2;    
    cout<<"下面比較兩個時間大小：\n";    
    if (c1>c2) cout<<"c1>c2"<<endl;    
    if (c1<c2) cout<<"c1<c2"<<endl;    
    if (c1==c2) cout<<"c1＝c2"<<endl;     
    if (c1!=c2) cout<<"c1≠c2"<<endl;    
    if (c1>=c2) cout<<"c1≥c2"<<endl;    
    if (c1<=c2) cout<<"c1≤c2"<<endl;    
    cout<<endl;    
    cout<<"c1+c2的數值爲：";    
    c=c1+c2;    
    cout<<c;  
    cout<<endl;  
    cout<<"c1-c2的數值爲：";    
    c=c1-c2;    
    cout<<c;    
    cout<<endl;    
    cout<<"c1*c2的數值爲：";    
    c=c1*c2;    
    cout<<c;  
    cout<<endl;  
    cout<<"c1/c2的數值爲：";    
    c=c1/c2;    
    cout<<c;   
    cout<<endl;  
    cout<<"對c1取反的結果爲：";  
    c=-c1;  
    cout<<c;  
    cout<<endl;  
	system("PAUSE");
}       

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