php僞造referer

CURL方式：

$ch = curl_init();

curl_setopt ($ch, CURLOPT_URL, "http://www.yyyy.com");

curl_setopt ($ch, CURLOPT_REFERER, "http://www.xxxx.com/");

curl_exec ($ch);

curl_close ($ch);

 

SOCKET方式：

$server = 'www.yyyy.com';

$host = 'www.yyyy.com';

$target = 'index.php';

$referer = 'http://www.xxxx.com/'; // Referer

$port = 80;

$fp = fsockopen($server, $port, $errno, $errstr, 30);

if (!$fp){

  echo "$errstr ($errno)\n";

}else{

$out = "GET $target HTTP/1.1\r\n";

$out .= "Host: $host\r\n";

$out .= "Referer: $referer\r\n";

$out .= "Connection: Close\r\n\r\n";

fwrite($fp, $out);

while (!feof($fp)){

echo fgets($fp, 128);

}

fclose($fp);

}

file_get_contents方法：

$opt=array('http'=>array('header'=>"Referer: $refer"));

$context=stream_context_create($opt);

$file_contents = file_get_contents($url,false, $context);

通過上面的代碼，我們就把referer地址僞裝爲http://www.xxxx.com，你可以寫一段代碼：

$_SERVER['HTTP_REFERER'];

查看到這個referer地址，就是這麼簡單，所以referer也不是什麼可靠的數據了