題目:
Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
思路:遞歸解決,根節點及左右子樹遞歸下去都要相等,只要有一個不等顯然就不等,所以用&&運算符連接,還有注意兩者都爲null返回true,一個null一個不爲null返回false,代碼如下:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if(p == null && q == null) {
return true;
} else {
if(p == null || q == null) {
return false;
} else {
return p.val == q.val && isSameTree(p.left,q.left) && isSameTree(p.right,q.right);
}
}
}
}