二分搜索的應用
#include <iostream>
#include <cstdio>
#include <iomanip>
using namespace std;
int intCables[10002];//單位cm
bool numberCuts(int index,int k,int length)//cm單位
{
long long lnums = 0;
for (int i = 0; i < index; ++i)
{
lnums += intCables[i]/length;
if (lnums >= k)return true;
}
return false;
}
int main()
{
freopen("in.txt","r",stdin);
int N,K;// 1 <= N, K <= 10000
int index = 0;
float fCable;
cin>>N>>K;
while (N--)
{
cin>>fCable;//單位是m
intCables[index++] = (int)(1000*fCable+5)/10;//轉換成cm存儲
}
int left = 1,right = 10000000;
int mid, ans = 0;
while (left <= right)
{
mid = (left + right)/2;
if (numberCuts(index,K,mid))
{
ans = mid; //這裏很關鍵
left = mid + 1;
}
else
right = mid - 1;
}
if (ans < 1)
cout<<"0.00"<<endl;
else
cout<<fixed<<setprecision(2)<<(ans*1.0/100)<<endl;
}
題目看錯了,小於1 cm才輸出0.00,我卻看成是小於1m,TMD! 提交了N次不通過