As a university advocating self-learning and work-rest balance, Marjar University has so many days of rest, including holidays and weekends. Each weekend, which consists of Saturday and Sunday, is a rest time in the Marjar University.
The May Day, also known as International Workers’ Day or International Labour Day, falls on May 1st. In Marjar University, the May Day holiday is a five-day vacation from May 1st to May 5th. Due to Saturday or Sunday may be adjacent to the May Day holiday, the continuous vacation may be as long as nine days in reality. For example, the May Day in 2015 is Friday so the continuous vacation is only 5 days (May 1st to May 5th). And the May Day in 2016 is Sunday so the continuous vacation is 6 days (April 30th to May 5th). In 2017, the May Day is Monday so the vacation is 9 days (April 29th to May 7th). How excited!
Edward, the headmaster of Marjar University, is very curious how long is the continuous vacation containing May Day in different years. Can you help him?
Input
There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case, there is an integer y (1928 <= y <= 9999) in one line, indicating the year of Edward’s query.
Output
For each case, print the number of days of the continuous vacation in that year.
Sample Input
3
2015
2016
2017
Output
5
6
9
思路：
題意是算一下五一放幾天假（週六週日也放假），那麼一共是三種情況。
第一種：如果五一那天是週一，放9天；
第二種：如果五一那天是週日或週二，放6天；
第三種：如果五一那天是週三或週四或週五或週六，放5天。
裏面還考了計算某一年的某一天是周幾，利用基姆拉爾森
森計算公式：int Week=(d+2m+3(m+1)/5+y+y/4-y/100+y/400+1)%7;
#include<bits/stdc++.h>
using namespace std;
int main()
{
std::ios::sync_with_stdio(false);
int t;
cin>>t;
while(t--)
{
int y;
cin>>y;
int m=5,d=1;
int Week=(d+2*m+3*(m+1)/5+y+y/4-y/100+y/400+1)%7;
if(Week==1)
cout<<9<<endl;
else if(Week==0||Week==2)
cout<<6<<endl;
else if(Week==3||Week==4||Week==5||Week==6)
cout<<5<<endl;
}
return 0;
}