題目描述
查找employees表所有emp_no爲奇數，且last_name不爲Mary的員工信息，並按照hire_date逆序排列
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
輸出描述
| emp_no | birth_date | first_name | last_name | gender | hire_date |
|---|---|---|---|---|---|
| 10011 | 1953-11-07 | Mary | Sluis | F | 1990-01-22 |
| 10005 | 1955-01-21 | Kyoichi | Maliniak | M | 1989-09-12 |
| 10007 | 1957-05-23 | Tzvetan | Zielinski | F | 1989-02-10 |
| 10003 | 1959-12-03 | Parto | Bamford | M | 1986-08-28 |
| 10001 | 1953-09-02 | Georgi | Facello | M | 1986-06-26 |
| 10009 | 1952-04-19 | Sumant | Peac | F | 1985-02-18 |
試題詳解
where語句中利用%餘數運算篩選奇數emp_no、利用<>篩選不等於'Mary'的僱員，之後根據僱傭日期倒敘輸出。代碼如下：
SELECT * FROM employees
WHERE emp_no%2 = 1
AND last_name <> 'Mary'
ORDER BY hire_date DESC;