表一結構:
ccpm_crm_customer
表二結構:
sys_user
現在根據表一中 CREATED_BY,UPDATED_BY關聯sys_user表user_id顯示爲username
sql:
SELECT
`OBJECT_SID`,
`CREATED`,
`LEADER`,
su1.username AS `CREATED_BY`,
`UPDATED`,
su2.username AS `UPDATED_BY`,
`ORG_SID`,
`IS_ACTIVE`,
`LOCK_VERSION`,
cc.`NAME` AS `NAME`,
`CONTACT_SID`,
`IS_TOP`,
`PARENT_SID`,
`IS_VIP`
FROM
(
SELECT
c.`OBJECT_SID`,
c.`CREATED`,
GROUP_CONCAT( su.username SEPARATOR ',' ) AS `LEADER`,
c.`CREATED_BY`,
c.`UPDATED`,
c.`UPDATED_BY`,
c.`ORG_SID`,
c.`IS_ACTIVE`,
c.`LOCK_VERSION`,
c.`NAME` AS `NAME`,
c.`CONTACT_SID`,
c.`IS_TOP`,
c.`PARENT_SID`,
c.`IS_VIP`
FROM
ccpm_crm_customer c
LEFT JOIN ccpm_user_customer cu ON c.OBJECT_SID = cu.customerId
LEFT JOIN sys_user su ON su.user_id = cu.uid
GROUP BY
c.OBJECT_SID
) cc
INNER JOIN sys_user su1 ON cc.CREATED_BY = su1.user_id
INNER JOIN sys_user su2 ON cc.UPDATED_BY = su2.user_id
因爲表一中兩個字段關聯表二id字段,所以要inner join兩次
這種查詢不能使用where判斷條件