leetcode-Hamming Distance

漢明碼距離

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given two integers x and y, calculate the Hamming distance.

Note:
0 ≤ x, y < 231.

Example:

Input: x = 1, y = 4

Output: 2

Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑

The above arrows point to positions where the corresponding bits are different.

class Solution {
public:
    int hammingDistance(int x, int y) {
        int dis = 0;
        int sx[32] = {0};
        int sy[32] = {0};
        int xi = 0;
        int yi = 0;
        while(x != 0){
            sx[xi++] = x % 2;
            x /= 2;
        }
        while(y != 0){
            sy[yi++] = y % 2;
            y /= 2;
        }
        for(int i = 0 ; i < 32; i++){
            if(sx[i] != sy[i]){
                dis++;
            }
        }
        return dis; 
    }
};