個人覺得:一個單例模式的工廠,永遠只維護一個類的實例,誰要訪問實例,工廠就返回這個實例,不會有副本。FlyWeight模式類似,一堆實例工廠,其中,每個實例都是獨一無二的,且沒有副本(因此隱含了工廠來管理對象的生命週期)。
參考的網絡例子太多沒注意內存泄漏,本人都作了完善。
如下:
#include<iostream>
#include<string>
#include<vector>
using std::cout;
using std::endl;
using std::string;
class Object
{
string mProperty;
public:
Object(string property)
:mProperty(property)
{}
string getProperty()
{
return mProperty;
}
virtual void Operation(string var) = 0;
virtual ~Object() {}
};
class MyObject:public Object
{
public:
MyObject(string property)
:Object(property)
{
cout << "create:" << property << endl;
}
virtual void Operation(string var)
{
//cout << getProperty() << endl;
//cout << var << endl;
}
virtual ~MyObject()
{
cout << "delete:" << getProperty() << endl;
}
};
class FlyWeightFactory
{
std::vector<Object*> objGroup;
public:
Object* getObj(string key)
{
for (auto const&obj : objGroup)
{
if (obj->getProperty()==key)
{
cout << "already exist:" << key << endl;
return obj;
}
}
Object* tempObj = new MyObject(key);
objGroup.push_back(tempObj);
return tempObj;
}
~FlyWeightFactory()
{
for (auto &obj : objGroup)
{
if (obj)
{
delete obj;
obj = 0;
}
}
}
};
int main()
{
{
FlyWeightFactory factory;
Object* m1 = factory.getObj("lee");
Object* m2 = factory.getObj("lucy");
Object* m3 = factory.getObj("lee");
}
return 0;
}