一、模型
二、表操作
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1、創建表結構
CREATE TABLE `dept` ( `id` int(11) NOT NULL AUTO_INCREMENT, `dept_name` varchar(32), PRIMARY KEY (`id`) ) ; CREATE TABLE `teacher` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(32) , `dept_id` int(11) , PRIMARY KEY (`id`), FOREIGN KEY (`dept_id`) REFERENCES `dept` (`id`) ) ; CREATE TABLE `course` ( `id` int(11) NOT NULL AUTO_INCREMENT, `course_name` varchar(32) , `teacher_id` int(11), PRIMARY KEY (`id`), FOREIGN KEY (`teacher_id`) REFERENCES `teacher` (`id`) ) ; CREATE TABLE `students` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(32) , `gender` tinyint(4) COMMENT '0:male,1:female', `birthday` date , `dept_id` int(11), PRIMARY KEY (`id`), FOREIGN KEY (`dept_id`) REFERENCES `dept` (`id`) ) ; CREATE TABLE `score` ( `sid` int(11), `course_id` int(11) , `score` tinyint(4), FOREIGN KEY (`course_id`) REFERENCES `course` (`id`), FOREIGN KEY (`sid`) REFERENCES `students` (`id`) ) ;
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2、插入測試數據
INSERT INTO `dept` VALUES (1,'Education'),(2,'Computer Science'),(3,'Mathematics'); INSERT INTO `teacher` VALUES (1,'Zhang san',1),(2,'Li si',1),(3,'Wang wu',2),(4,'Liu liu',3),(5,'Ding \nqi',3),(6,'Zhang yang',2); INSERT INTO `course` VALUES (1,'math',3),(2,'english',2),(3,'chinese',4),(4,'history',1),(5,'biology',5),(6,'physical',2); INSERT INTO `students` VALUES (1,'Andrew',0,'1985-08-05',1),(2,'Andy',0,'1983-02-09',1),(3,'Bob',0,'1983-01-03',1),(4,'Ruth',1,'1984-12-23',2),(5,'Mike',0,'1985-01-02',2),(6,'John',0,'1984-02-23',3),(7,'Cindy',1,'1984-12-04',3),(8,'Susan',1,'1983-11-11',3),(9,'John',1,'1984-09-18',2),(10,'Esther',1,'1988-12-25',3); INSERT INTO `score` VALUES (1,1,56),(1,2,90),(1,3,82),(1,5,56),(2,2,78),(2,4,92),(2,3,77),(2,5,65),(3,1,48),(3,2,95),(3,3,75),(3,4,89),(3,5,92),(4,3,78),(4,4,67),(5,1,75),(5,3,90),(5,4,82),(6,2,58),(6,4,88),(7,1,46),(7,2,65),(7,3,63),(7,4,68),(7,5,32),(8,4,88),(8,5,100),(1,6,76),(2,6,54),(4,6,98),(5,6,87),(8,6,76),(9,1,90),(9,2,59),(10,3,67);
三、練習題
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1、查詢85年之後出生的學生人數
SELECT COUNT(*) FROM `students` WHERE `birthday` >'1985-01-01'
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2、查詢名字相同的學生名單和個數
SELECT `name`, COUNT(*) FROM `students` GROUP BY `name`
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3、將所有學生姓名中前後的空格去掉、
SELECT TRIM(`name`) FROM `students`
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4 、查看每門課程被選修的學生數
SELECT `course_id`,COUNT(`sid`) FROM `score` GROUP BY `course_id`
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5、查詢姓zhang的老師的個數
SELECT COUNT(*) FROM `teacher` WHERE SUBSTRING_INDEX(`name`,' ',1) = 'Zhang'
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6 、將所有老師的名字拆分成姓和名兩個字段顯示
SELECT SUBSTRING(`name`, 1, LOCATE(' ', `name`)) '姓', -- locate()返回子串位置 SUBSTRING_INDEX(`name`, ' ', - 1) '名' -- 推薦使用SUBSTRING_INDEX() FROM `teacher`
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7、把所有學生的生日格式轉換成年月日的格式,並計算每個學生年齡
SELECT `name`, DATE_FORMAT(`birthday`, '%Y%m%d'), FLOOR(DATEDIFF(NOW(), `birthday`) / 365) '年齡' FROM `students`
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8、查詢有不及格學生的課程和不及格學生個數
SELECT b.`course_name`, COUNT(*) FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` WHERE a.`score` < 60 GROUP BY a.`course_id`
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9、查詢每門課程的平均成績,按升序排序,如果平均成績相同按課程ID降序排序
SELECT b.`course_name`, AVG(a.`score`) FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` GROUP BY a.`course_id` ORDER BY AVG(a.`score`),a.`course_id` DESC
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10、查詢有學生的單科成績小於60的姓名和課程名稱
SELECT b.`name`, c.`course_name` FROM `score` a JOIN `students` b ON a.`sid` = b.`id` JOIN `course` c ON a.`course_id` = c.`id` WHERE a.`score` < 60
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11、查看平均成績大於等於60的所有學生的姓名和平均成績
SELECT any_value (b.`name`), AVG(a.`score`) FROM `score` a JOIN `students` b ON a.`sid` = b.`id` GROUP BY b.`id` HAVING AVG(a.`score`) > 60
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12、將所有學生的考試成績展示爲課程名:成績樣式
SELECT a.`sid`, CONCAT(b.`course_name`, ':', a.`score`) FROM `score` a JOIN `course` b ON a.`course_id` = b.`id`
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13、查詢不同老師所教不同課程平均分從高到低
SELECT b.`teacher_id`, b.`id` -- 課程ID FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` GROUP BY b.`teacher_id`, b.`id` ORDER BY AVG(a.`score`) DESC
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14、查詢英語課程成績排名第3到第5位的學生姓名和成績
SELECT b.`name`, a.`score` FROM `score` a JOIN `students` b ON a.`sid` = b.`id` JOIN `course` c ON a.`course_id` = c.`id` WHERE c.`course_name` = 'english' ORDER BY a.`score` DESC LIMIT 2, 3
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15、查詢所有同學的學號,姓名,選課數和總成績
SELECT a.`sid`, b.`name`, COUNT(a.`course_id`), SUM(a.`score`) FROM `score` a JOIN `students` b ON a.`sid` = b.`id` GROUP BY b.`id`
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16、查詢各科成績中的最高分和最低分
SELECT b.`course_name`, MAX(a.`score`), MIN(a.`score`) FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` GROUP BY b.`course_name`
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17、計算各科平均成績和及格率百分比
SELECT b.`course_name`, AVG(a.`score`), SUM(IF(a.`score`>=60,1,0))/COUNT(*) FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` GROUP BY b.`course_name`
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18、查看只學習了一門課程的學生的姓名和學號
SELECT `id`, `name` FROM `students` WHERE `id` = (SELECT `sid` FROM `score` GROUP BY `sid` HAVING COUNT(`course_id`)=1)
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19、查詢沒學過zhangsan老師課程的學生的學號和姓名
SELECT `id`, `name` FROM `students` WHERE `id` NOT IN (SELECT DISTINCT a.`sid` FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` JOIN `teacher` c ON b.`teacher_id` = c.`id` WHERE c.`name` = 'Zhang san')
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20、查詢既學過英語也學過語文的學生的學號和姓名
SELECT b.`id`, b.`name`, GROUP_CONCAT(c.`course_name`) FROM `score` a JOIN `students` b ON a.`sid` = b.`id` JOIN `course` c ON a.`course_id` = c.`id` WHERE c.`course_name` IN ('english', 'chinese') GROUP BY b.`id` HAVING COUNT(*) >1
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21、按平均成績從高到低顯示所有學生的姓名和語文,數學,英語三科成績
SELECT any_value(b.`name`), SUM(CASE WHEN c.`course_name`='chinese' THEN a.score ELSE 0 END) 'chinese', SUM(IF(c.`course_name`='math',a.`score`,0)) 'math', SUM(IF(c.`course_name`='english',a.`score`,0)) 'english' FROM `score` a JOIN `students` b ON a.`sid` = b.`id` JOIN `course` c ON a.`course_id` = c.`id` GROUP BY a.`sid` ORDER BY AVG(a.`score`) DESC
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22、統計按照各科成績,分段統計每個課程在90分以上、80-90的、60~80、低於60分的人數
SELECT b.`course_name`, SUM(IF(a.`score`>=90,1,0)) '90分以上', SUM(IF(a.`score`<90 AND a.`score`>=80,1,0)) '80~90分', SUM(IF(a.`score`<80 AND a.`score`>=60,1,0)) '60~80分', SUM(IF(a.`score`<60,1,0)) '不及格' FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` GROUP BY b.`course_name`
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23、查看所有英語成績超過數學成績的學生的學號和姓名
SELECT a.`id`,a.`name`,c.`score`, b.`score` FROM `students` a JOIN (SELECT a.`sid`,a.`score` FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` WHERE b.`course_name` = 'math') b ON a.`id` = b.`sid` JOIN (SELECT a.`sid`,a.`score` FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` WHERE b.`course_name` = 'english') c ON a.`id` = c.`sid` WHERE c.`score`> b.`score`