MySQL之SQL訓練(一)

一、模型

在這裏插入圖片描述

二、表操作

  • 1、創建表結構

    CREATE TABLE `dept` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `dept_name` varchar(32),
      PRIMARY KEY (`id`)
    ) ;
    
    CREATE TABLE `teacher` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `name` varchar(32) ,
      `dept_id` int(11) ,
      PRIMARY KEY (`id`),
      FOREIGN KEY (`dept_id`) REFERENCES `dept` (`id`)
    ) ;
    
    CREATE TABLE `course` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `course_name` varchar(32) ,
      `teacher_id` int(11),
      PRIMARY KEY (`id`),
      FOREIGN KEY (`teacher_id`) REFERENCES `teacher` (`id`)
    ) ;
    
    CREATE TABLE `students` (
      `id` int(11) NOT NULL AUTO_INCREMENT,
      `name` varchar(32) ,
      `gender` tinyint(4)  COMMENT '0:male,1:female',
      `birthday` date ,
      `dept_id` int(11),
      PRIMARY KEY (`id`),
      FOREIGN KEY (`dept_id`) REFERENCES `dept` (`id`)
    ) ;
    
    CREATE TABLE `score` (
      `sid` int(11),
      `course_id` int(11) ,
      `score` tinyint(4),
      FOREIGN KEY (`course_id`) REFERENCES `course` (`id`),
      FOREIGN KEY (`sid`) REFERENCES `students` (`id`)
    ) ;
    
  • 2、插入測試數據

    INSERT INTO `dept` VALUES (1,'Education'),(2,'Computer Science'),(3,'Mathematics');
    
    INSERT INTO `teacher` VALUES (1,'Zhang san',1),(2,'Li si',1),(3,'Wang wu',2),(4,'Liu liu',3),(5,'Ding \nqi',3),(6,'Zhang yang',2);
    
    INSERT INTO `course` VALUES (1,'math',3),(2,'english',2),(3,'chinese',4),(4,'history',1),(5,'biology',5),(6,'physical',2);
    
    INSERT INTO `students` VALUES (1,'Andrew',0,'1985-08-05',1),(2,'Andy',0,'1983-02-09',1),(3,'Bob',0,'1983-01-03',1),(4,'Ruth',1,'1984-12-23',2),(5,'Mike',0,'1985-01-02',2),(6,'John',0,'1984-02-23',3),(7,'Cindy',1,'1984-12-04',3),(8,'Susan',1,'1983-11-11',3),(9,'John',1,'1984-09-18',2),(10,'Esther',1,'1988-12-25',3);
    
    INSERT INTO `score` VALUES (1,1,56),(1,2,90),(1,3,82),(1,5,56),(2,2,78),(2,4,92),(2,3,77),(2,5,65),(3,1,48),(3,2,95),(3,3,75),(3,4,89),(3,5,92),(4,3,78),(4,4,67),(5,1,75),(5,3,90),(5,4,82),(6,2,58),(6,4,88),(7,1,46),(7,2,65),(7,3,63),(7,4,68),(7,5,32),(8,4,88),(8,5,100),(1,6,76),(2,6,54),(4,6,98),(5,6,87),(8,6,76),(9,1,90),(9,2,59),(10,3,67);
    

三、練習題

  • 1、查詢85年之後出生的學生人數

    SELECT COUNT(*) FROM `students` WHERE `birthday` >'1985-01-01'
    
  • 2、查詢名字相同的學生名單和個數

    SELECT `name`, COUNT(*) FROM `students` GROUP BY `name` 
    
  • 3、將所有學生姓名中前後的空格去掉、

    SELECT TRIM(`name`) FROM `students`
    
  • 4 、查看每門課程被選修的學生數

    SELECT `course_id`,COUNT(`sid`) FROM `score` GROUP BY `course_id`
    
  • 5、查詢姓zhang的老師的個數

    SELECT COUNT(*) FROM `teacher` WHERE SUBSTRING_INDEX(`name`,' ',1) = 'Zhang'
    
  • 6 、將所有老師的名字拆分成姓和名兩個字段顯示

    SELECT
      SUBSTRING(`name`, 1, LOCATE(' ', `name`)) '姓', -- locate()返回子串位置
      SUBSTRING_INDEX(`name`, ' ', - 1) '名' -- 推薦使用SUBSTRING_INDEX()
    FROM
      `teacher`
    
  • 7、把所有學生的生日格式轉換成年月日的格式,並計算每個學生年齡

    SELECT
      `name`,
      DATE_FORMAT(`birthday`, '%Y%m%d'),
      FLOOR(DATEDIFF(NOW(), `birthday`) / 365) '年齡'
    FROM
      `students`
    
  • 8、查詢有不及格學生的課程和不及格學生個數

    SELECT
      b.`course_name`,
      COUNT(*)
    FROM
      `score` a
      JOIN `course` b
        ON a.`course_id` = b.`id`
    WHERE a.`score` < 60
    GROUP BY a.`course_id`
    
  • 9、查詢每門課程的平均成績,按升序排序,如果平均成績相同按課程ID降序排序

    SELECT
      b.`course_name`,
      AVG(a.`score`)
    FROM
      `score` a
      JOIN `course` b
        ON a.`course_id` = b.`id`
    GROUP BY a.`course_id`
    ORDER BY AVG(a.`score`),a.`course_id` DESC
    
  • 10、查詢有學生的單科成績小於60的姓名和課程名稱

    SELECT
      b.`name`,
      c.`course_name`
    FROM
      `score` a
      JOIN `students` b
        ON a.`sid` = b.`id`
      JOIN `course` c
        ON a.`course_id` = c.`id`
    WHERE a.`score` < 60
    
  • 11、查看平均成績大於等於60的所有學生的姓名和平均成績

    SELECT
      any_value (b.`name`),
      AVG(a.`score`)
    FROM
      `score` a
      JOIN `students` b
        ON a.`sid` = b.`id`
    GROUP BY b.`id`
    HAVING AVG(a.`score`) > 60
    
  • 12、將所有學生的考試成績展示爲課程名:成績樣式

    SELECT
      a.`sid`,
      CONCAT(b.`course_name`, ':', a.`score`)
    FROM
      `score` a
      JOIN `course` b
        ON a.`course_id` = b.`id`
    
  • 13、查詢不同老師所教不同課程平均分從高到低

    SELECT
      b.`teacher_id`,
      b.`id` -- 課程ID
    FROM
      `score` a
      JOIN `course` b
        ON a.`course_id` = b.`id`
    GROUP BY b.`teacher_id`, b.`id`
    ORDER BY AVG(a.`score`) DESC
    
  • 14、查詢英語課程成績排名第3到第5位的學生姓名和成績

    SELECT
      b.`name`,
      a.`score`
    FROM
      `score` a
      JOIN `students` b
        ON a.`sid` = b.`id`
      JOIN `course` c
        ON a.`course_id` = c.`id`
    WHERE c.`course_name` = 'english'
    ORDER BY a.`score` DESC
    LIMIT 2, 3
    
  • 15、查詢所有同學的學號,姓名,選課數和總成績

    SELECT
      a.`sid`,
      b.`name`,
      COUNT(a.`course_id`),
      SUM(a.`score`)
    FROM
      `score` a
      JOIN `students` b
        ON a.`sid` = b.`id`
    GROUP BY b.`id`
    
  • 16、查詢各科成績中的最高分和最低分

    SELECT
      b.`course_name`,
      MAX(a.`score`),
      MIN(a.`score`)
    FROM
      `score` a
      JOIN `course` b
        ON a.`course_id` = b.`id`
    GROUP BY b.`course_name`
    
  • 17、計算各科平均成績和及格率百分比

    SELECT
      b.`course_name`,
      AVG(a.`score`),
      SUM(IF(a.`score`>=60,1,0))/COUNT(*)
    FROM
      `score` a
      JOIN `course` b
        ON a.`course_id` = b.`id`
    GROUP BY b.`course_name`
    
  • 18、查看只學習了一門課程的學生的姓名和學號

    SELECT
      `id`,
      `name`
    FROM
      `students`
    WHERE `id` = (SELECT `sid` FROM `score` GROUP BY `sid` HAVING COUNT(`course_id`)=1)
    
  • 19、查詢沒學過zhangsan老師課程的學生的學號和姓名

    SELECT
      `id`,
      `name`
    FROM
      `students`
    WHERE `id` NOT IN
      (SELECT DISTINCT
        a.`sid`
      FROM
        `score` a
        JOIN `course` b
          ON a.`course_id` = b.`id`
        JOIN `teacher` c
          ON b.`teacher_id` = c.`id`
      WHERE c.`name` = 'Zhang san')
    
  • 20、查詢既學過英語也學過語文的學生的學號和姓名

    SELECT
      b.`id`,
      b.`name`,
      GROUP_CONCAT(c.`course_name`)
    FROM
      `score` a
      JOIN `students` b
        ON a.`sid` = b.`id`
      JOIN `course` c
        ON a.`course_id` = c.`id`
    WHERE c.`course_name` IN ('english', 'chinese')
    GROUP BY b.`id`
    HAVING COUNT(*) >1
    
  • 21、按平均成績從高到低顯示所有學生的姓名和語文,數學,英語三科成績

    SELECT
      any_value(b.`name`),
      SUM(CASE WHEN c.`course_name`='chinese' THEN a.score ELSE 0 END) 'chinese',
      SUM(IF(c.`course_name`='math',a.`score`,0)) 'math',
      SUM(IF(c.`course_name`='english',a.`score`,0)) 'english'
    FROM
      `score` a
      JOIN `students` b
        ON a.`sid` = b.`id`
      JOIN `course` c
        ON a.`course_id` = c.`id`
    GROUP BY a.`sid`
    ORDER BY AVG(a.`score`) DESC
    
  • 22、統計按照各科成績,分段統計每個課程在90分以上、80-90的、60~80、低於60分的人數

    SELECT
      b.`course_name`,
      SUM(IF(a.`score`>=90,1,0)) '90分以上',
      SUM(IF(a.`score`<90 AND a.`score`>=80,1,0)) '80~90分',
      SUM(IF(a.`score`<80 AND a.`score`>=60,1,0)) '60~80分',
      SUM(IF(a.`score`<60,1,0)) '不及格'
    FROM
      `score` a
      JOIN `course` b
        ON a.`course_id` = b.`id`
    GROUP BY b.`course_name`
    
  • 23、查看所有英語成績超過數學成績的學生的學號和姓名

    SELECT
      a.`id`,a.`name`,c.`score`, b.`score` 
    FROM
      `students` a
      JOIN (SELECT a.`sid`,a.`score` FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` WHERE b.`course_name` = 'math') b
        ON a.`id` = b.`sid`
      JOIN (SELECT a.`sid`,a.`score` FROM `score` a JOIN `course` b ON a.`course_id` = b.`id` WHERE b.`course_name` = 'english') c  
        ON a.`id` = c.`sid`
    WHERE c.`score`> b.`score` 
    
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