目錄
文章涉及到的MySQL、SQLyog的配置安裝,請參考 MySQL配置+SQLyog安裝教程
SELECT嵌套SELECT
含義
出現在其他語句中的select語句,稱爲子查詢或者內查詢,外部的查詢語句,稱爲主查詢,或者外查詢。
分類
按字查詢出現的位置
- select後面:僅僅支持標量子查詢
- from後面:支持表子查詢
- where、having後面:支持標量子查詢;列子查詢;行子查詢
- exists後面(相關子查詢):支持表子查詢
按結果集的不同
- 標量子查詢(結果集只有一行一列)
- 列子查詢(結果集只有一列,但是多行)
- 行子子查詢(結果集可以是多行多列)
- 表子查詢(結果集隨意,一般爲多行多列)
一、where、having後面
特點
- 子查詢放在小括號內
- 子查詢一般放在條件右側
- 標量查詢,一般搭配着單行操作符使用,例如:<、>、>=、<=、=、<>
- 列子查詢,一般搭配多行操作符使用,in、all/some、all
- 子查詢的執行優先於主查詢的執行,因爲子查詢的結果是主查詢的條件
1、標量子查詢
#案例1:誰的工資比 Abel 高?
#step1. 查詢Abel的工資
SELECT salary
FROM employees
WHERE last_name = 'Abel';
#step2.查詢員工的信息,滿足salary大於1的結果
SELECT *
FROM employees
WHERE salary >(
SELECT salary
FROM employees
WHERE last_name = 'Abel'
);
#案例2:返回job_id與141號員工相同,salary比143號員工多的員工 姓名,job_id和工資
#step1.查詢141號員工的job_id
SELECT job_id
FROM employees
WHERE employee_id = 141;
#step2.查詢143號員工的salary
SELECT salary
FROM employees
WHERE employee_id = 143;
#step3.
SELECT last_name, job_id, salary
FROM employees
WHERE job_id = (
SELECT job_id
FROM employees
WHERE employee_id = 141
)
AND salary > (
SELECT salary
FROM employees
WHERE employee_id = 143
);
#案例3:返回公司工資最少的員工的last_name, job_id,salary
SELECT last_name, job_id, salary
FROM employees
WHERE salary=(
SELECT MIN(salary)
FROM employees
);
#案例4:查詢最低工資大於50號部門最低工資的部門id和其最低工資
#step1.50號部門的最低工資
SELECT MIN(salary)
FROM employees
WHERE department_id=50;
#step2.
SELECT department_id, MIN(salary)
FROM employees
GROUP BY department_id
HAVING MIN(salary)>(
SELECT MIN(salary)
FROM employees
WHERE department_id=50
);
注意:非法使用標量子查詢的問題
SELECT department_id, MIN(salary)
FROM employees
GROUP BY department_id
HAVING MIN(salary)>(
SELECT salary # 不是一行一列
FROM employees
WHERE department_id=50
);
2、列子查詢
多行操作符
- in/not in:相當於列表中的任意一個(in相當於=any;not in相當於<>all)
- any/some:和子查詢返回的某一個值比較,只要滿足其中一個就可以,經常可以被MIN或者MAX替代
- all:和子查詢返回的所有值比較
#案例1:返回location_id是1400或者1700的部門中的所有員工姓名
#step1.查詢location_id是1400或1700的部門編號
SELECT DISTINCT department_id
FROM departments
WHERE location_id = 1400
OR location_id = 1700;
#step2.查詢員工姓名,要求部門號是1列表中的某一個
SELECT last_name
FROM employees
WHERE department_id IN (
SELECT DISTINCT department_id
FROM departments
WHERE location_id = 1400
OR location_id = 1700
);
#案例2:返回其他工種中比job_id爲‘IT_PROG’工種任一工資低的員工的:工號、姓名、job_id 以及salary
#step1.
SELECT salary
FROM employees
WHERE job_id='IT_PROG';
#step2.
SELECT department_id, last_name, job_id, salary
FROM employees
WHERE salary < ANY(
SELECT DISTINCT salary
FROM employees
WHERE job_id='IT_PROG'
)
AND job_id<>'IT_PROG';
案例2可以進行如下書寫代替
SELECT department_id, last_name, job_id, salary
FROM employees
WHERE salary < (
SELECT MAX(salary)
FROM employees
WHERE job_id='IT_PROG'
)
AND job_id<>'IT_PROG';
#案例3:返回其他工種中比job_id爲'IT_PROG'工種所有工資都低的員工的工號、姓名、job_id、以及salary
SELECT department_id, last_name, job_id, salary
FROM employees
WHERE salary < ALL(
SELECT DISTINCT salary
FROM employees
WHERE job_id='IT_PROG'
)
AND job_id<>'IT_PROG';
案例3可以進行如下書寫代替
SELECT department_id, last_name, job_id, salary
FROM employees
WHERE salary < (
SELECT MIN(salary)
FROM employees
WHERE job_id='IT_PROG'
)
AND job_id<>'IT_PROG';
3、行子查詢
#案例:查詢員工編號最小並且工資最高的員工信息
#非行子查詢版本
#step1.
SELECT MIN(employee_id)
FROM employees;
#step2.
SELECT MAX(salary)
FROM employees;
#step3.
SELECT *
FROM employees
WHERE employee_id=(
SELECT MIN(employee_id)
FROM employees
)
AND salary=(
SELECT MAX(salary)
FROM employees
);
#行子查詢版本
SELECT *
FROM employees
WHERE (employee_id, salary)=(
SELECT MIN(employee_id), MAX(salary)
FROM employees
);
二、select後面
#案例1:查詢每個部門的員工個數
SELECT d.*, (
SELECT COUNT(*)
FROM employees e
WHERE e.department_id = d.`department_id`
)
FROM departments d;
#案例2:查詢員工號爲102的部門名
SELECT (
SELECT department_name
FROM departments d
INNER JOIN employees e
ON d.department_id=e.department_id
WHERE e.employee_id = 102
) 部門名;
三、from後面
將子查詢結果充當一張表,必須起別名
#案例:查詢每個部門的平均工資的工資等級
#step1.
SELECT AVG(salary), department_id
FROM employees
GROUP BY department_id;
#step2.連接1的結果集與job_grades表
SELECT ag_dep.*, g.`grade_level`
FROM (
SELECT AVG(salary) ag, department_id
FROM employees
GROUP BY department_id
) ag_dep
INNER JOIN job_grades g
ON ag_dep.ag BETWEEN g.`lowest_sal` AND g.`highest_sal`;
四、exists後面
語法
exists(完整的查詢語句)
返回結果:1或者0
#案例1:查詢有員工名的部門名
SELECT department_name
FROM departments d
WHERE EXISTS(
SELECT *
FROM employees e
WHERE d.`department_id`=e.`department_id`
);
#使用in代替exists
SELECT department_name
FROM departments d
WHERE d.`department_id` IN(
SELECT department_id
FROM employees
);
#案例2:查詢沒有女朋友的男生信息
#in
SELECT bo.*
FROM boys bo
WHERE bo.id NOT IN(
SELECT boyfriend_id
FROM beauty
);
#exists
SELECT bo.*
FROM boys bo
WHERE NOT EXISTS(
SELECT boyfriend_id
FROM beauty b
WHERE bo.`id`=b.`boyfriend_id`
);