Leetcode: Binary Tree Postorder Traversal

Given a binary tree, return the postorder traversal of its nodes' values.

For example:
Given binary tree {1,#,2,3},

   1
    \
     2
    /
   3

return [3,2,1].

Note: Recursive solution is trivial, could you do it iteratively?

/**
 * Definition for binary tree
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public ArrayList<Integer> postorderTraversal(TreeNode root) {
        // IMPORTANT: Please reset any member data you declared, as
        // the same Solution instance will be reused for each test case.
        ArrayList<Integer> res = new ArrayList<Integer>();
        if(root == null)
            return res;
        TreeNode pre = null;
        TreeNode cur = null;
        Stack<TreeNode> stack = new Stack<TreeNode>();
        stack.push(root);
        while(!stack.isEmpty()){
            cur = stack.peek();
            if(pre == null || (pre != null && (pre.left == cur || pre.right == cur))){
                if(cur.left != null)
                    stack.push(cur.left);
                else if(cur.right != null)
                    stack.push(cur.right);
            } else if (cur.left == pre){
                if(cur.right != null)
                    stack.push(cur.right);
            } else {
                res.add(stack.pop().val);
            }
            pre = cur;
        }
        return res;
    }
}



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