import java.util.*;
class Step{
int x,y,d;
public Step(int x,int y,int d) {
this.x = x;//橫座標
this.y = y;//縱座標
this.d = d;//方向
}
}
public class Main3 {
public static int getnum(int x1,int y1,int x2,int y2){
return (x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);
}
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
while(sc.hasNextInt()){
//構造迷宮
int n=sc.nextInt();
int m=sc.nextInt();
int[][] maze=new int[n][m];
ArrayList<int[][]> list = new ArrayList<int[][]>();
for(int i = 0; i < n; ++i) {
String str=sc.next();
for(int j = 0; j < m; ++j) {
char c= str.charAt(j);
if(c=='.'){
maze[i][j] = 0;
int[][] endij=new int[1][2];
endij[0][0]=i+1;
endij[0][1]=j+1;
list.add(endij);
}else{
maze[i][j] = 1;
}
}
}
int begini=sc.nextInt()+1;
int beginj=sc.nextInt()+1;
int max=0;
int endi=0;
int endj=0;
for(int i=0;i<list.size();i++){
int temp=getnum(list.get(i)[0][0],list.get(i)[0][1],begini,beginj);
if(temp>max){
max=temp;
endi=list.get(i)[0][0];
endj=list.get(i)[0][1];
}
}
int k=sc.nextInt();
int[][] move=new int[k][2];
for(int i=0;i<k;i++){
for(int j=0;j<2;j++){
move[i][j]=sc.nextInt();
}
}
Stack s = new Stack();
Stack s1 = new Stack();
int a = path(maze, move, s,begini,beginj,endi,endj);
if(s.isEmpty()){
System.out.println("-1");
}else{
System.out.println(s.size());
}
}
}
public static int path(int[][] maze,int[][] move,Stack s,int begini,int beginj,int endi,int endj){
Step temp = new Step(begini,beginj,-1); //起點
s.push(temp);
while(!s.isEmpty()){
temp = (Step) s.pop();
int x = temp.x;
int y = temp.y;
int d = temp.d+1;
while(d<move.length){
int i = x + move[d][0];
int j = y + move[d][1];
if(i<=maze.length-1 && j<=maze[0].length-1 && maze[i][j] == 0){ //該點可達
temp = new Step(i,j,d); //到達新點
s.push(temp);
x = i;
y = j;
maze[x][y] = -1; //到達新點,標誌已經到達
if(x == endi && y == endj){
return 1; //到達出口,迷宮有路,返回1
}else{
d = 0; //重新初始化方向
}
}else{
d++; //改變方向
}
}
}
return 0;
}
}
(java)簡單回朔法解決迷宮問題
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