翻轉單詞順序列
牛客最近來了一個新員工Fish,每天早晨總是會拿着一本英文雜誌,寫些句子在本子上。同事Cat對Fish寫的內容頗感興趣,有一天他向Fish借來翻看,但卻讀不懂它的意思。例如,“student. a am I”。後來才意識到,這傢伙原來把句子單詞的順序翻轉了,正確的句子應該是“I am a student.”。Cat對一一的翻轉這些單詞順序可不在行,你能幫助他麼?
# -*- coding:utf-8 -*-
class Solution:
def ReverseSentence(self, s):
# write code here
words=s.split()
if len(words)==0:
return s
reverse_words=words[::-1]
return " ".join(reverse_words)
撲克牌順子
LL今天心情特別好,因爲他去買了一副撲克牌,發現裏面居然有2個大王,2個小王(一副牌原本是54張_)…他隨機從中抽出了5張牌,想測測自己的手氣,看看能不能抽到順子,如果抽到的話,他決定去買體育彩票,嘿嘿!!“紅心A,黑桃3,小王,大王,方片5”,“Oh My God!”不是順子…LL不高興了,他想了想,決定大\小 王可以看成任何數字,並且A看作1,J爲11,Q爲12,K爲13。上面的5張牌就可以變成“1,2,3,4,5”(大小王分別看作2和4),“So Lucky!”。LL決定去買體育彩票啦。 現在,要求你使用這幅牌模擬上面的過程,然後告訴我們LL的運氣如何, 如果牌能組成順子就輸出true,否則就輸出false。爲了方便起見,你可以認爲大小王是0。
# -*- coding:utf-8 -*-
class Solution:
def IsContinuous(self, numbers):
# write code here
if not numbers:
return False
num_king = numbers.count(0)
sorted_numbers = sorted(numbers)
length = len(numbers)
num_need = 0
for i in range(1, length):
if sorted_numbers[i] != 0 and sorted_numbers[i-1]!=0:
diff = sorted_numbers[i] - sorted_numbers[i - 1]
if diff > 1 and diff-1 <= num_king:
num_need += diff - 1
if num_need > num_king:
return False
else:
continue
elif diff==1:
continue
return False
return True
# 精簡版(思路基本相同):
鏈接:https://www.nowcoder.com/questionTerminal/762836f4d43d43ca9deb273b3de8e1f4?f=discussion
來源:牛客網
def IsContinuous(self, numbers):
if not numbers:return False
numbers.sort()
zeroNum = numbers.count(0)
for i, v in enumerate(numbers[:-1]):
if v != 0:
if numbers[i+1]==v:return False
zeroNum = zeroNum - (numbers[i + 1] - v) + 1
if zeroNum < 0:
return False
return True