Uva.202 Repeating Decimals

//模擬人腦計算有理數的循環節
#include<iostream>
#include<cstdio>
using namespace std;
const int maxn = 10000;
int decimal[maxn];
struct node {
	int a, b;
};
node mark[maxn];
int visited(int a, int b, int len);
int main() {
	//freopen("Text.txt", "r", stdin);
	int a, b;
	while (scanf("%d %d", &a, &b)!=EOF) {
		int i, j, x, cnt=1;
		for (i = 0; i < maxn; i++) {//初始化
			decimal[i] = -1;
			mark[i].b = b;
		}
		decimal[0] = a / b;//計算整數部分
		x = a%b * 10;
		while (1) {
			decimal[cnt] = x / b;
			mark[cnt].a = x;
			if (visited(x, b, cnt))break;
			x = x%b * 10;
			cnt++;
		}
		//for (i = 0; i <= cnt; i++)printf("%d", decimal[i]);
		//cout << endl;
		int begin = visited(mark[cnt].a, mark[cnt].b, cnt);
		//printf("begin=%d\n", begin);
		//for (i = 1; i <= cnt; i++) printf("a = %d,b = %d\n", mark[i].a, mark[i].b);
		

			cnt--;
			//輸出部分
			if (cnt > 50) {
				printf("%d/%d = %d.", a, b, decimal[0]);
				for (i = 1; i < begin; i++)printf("%d", decimal[i]);
				printf("(");
				for (i = begin; i <= 50; i++)printf("%d", decimal[i]);
				printf("...)\n");
				printf("   %d = number of digits in repeating cycle\n\n", cnt-begin+1);
			}
			else {
				printf("%d/%d = %d.", a, b, decimal[0]);
				for (i = 1; i < begin; i++)printf("%d", decimal[i]);
				printf("(");
				for (i = begin; i <= cnt; i++)printf("%d", decimal[i]);
				printf(")\n");
				printf("   %d = number of digits in repeating cycle\n\n", cnt-begin+1);
			}
	}
	return 0;
}
int visited(int a, int b, int len) {//利用分子分母相同計算循環節的開始
	for (int i = 1; i < len; i++) {
		if (mark[i].a == a&&mark[i].b == b)
			return i;
	}
	return 0;
}

題目鏈接：

https://vjudge.net/problem/UVA-202