收到推送通知後頁面跳轉,當程序在後臺，無論進入後臺之前在哪個界面，點擊收到的推送，跳轉到指定界面的2個思路：

發個廣告：ios開發兩年了，一步步走來  關注公衆號一起進步

發現一篇文章 正好解決自己的問題，在此記錄一下

方法一：

-(void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo{
    if( ){
        PushViewController *push = [PushViewController alloc] init];
       [self.window.rootViewController presentViewController:push animated:YES completion:nil];
    }

}

方法二：（個人感覺這個可靠些）
做一個基類：基類的viewwillappear裏做操作，其它頁面繼承這個類
基本上想怎麼跳就怎麼跳：

//-----------------------------------1

@interface BasicViewController : UIViewController
@end
....

.m裏
- (void)viewWillAppear:(BOOL)animated
{
    [super viewWillAppear:animated];
    [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(gotoMessageView:) name:@"gotoMessageView"object:nil];
}
-(void)viewWillDisappear:(BOOL)animated
{
    [super viewWillDisappear:animated];
    [[NSNotificationCenter defaultCenter] removeObserver:self name:@"gotoMessageView" object:nil];
}
// 這裏區分消息  進行頁面跳轉
- (void) gotoMessageView:(NSNotification*) notification
{
   //.....
}
//----------------2
其他viewcontroller：
@interface AViewController : BasicViewController
.....
-(void)viewWillDisappear:(BOOL)animated
{
    [super viewWillDisappear:animated];
}
//----------3
-(void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{
......

 [[NSNotificationCenter defaultCenter] postNotificationName:@"gotoMessageView" object:nil];
}