# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def hasCycle(self, head: ListNode) -> bool:
slow = fast = head
while fast and fast.next:
slow = slow.next
fast = fast.next.next
if fast == slow:
return True
return False
leetcode 環形鏈表 python3
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